How to Calculate Spring Constant and Stretch Distance

[Ashford]

3. A certain Spring will stretch 5.0 cm when a force of 12 N is applied to it.
a. Calculate its spring constant in its elastic region.
I got K=F/X so 12/.5 which comes out to be 2.4

b. If a force of 25 N were applied to the same spring, how much would it stretch?
I got x = f/K so 25/2.4 which comes out to be 10.42 cm.

Is this correct?

Online

 

[Kurdt]

Yes it looks ok. In the first part however you have 12/.5 and quoted the correct answer in N/cm. I'm guessing it was a typo.

 

[lavalamp]

Actually it would have been in N/dm (decimetre), since Ashford divided the distance stretched by 10 instead of 100.

Edit: Ah yes, I see what you mean. So ... hah, ignore this.