How Do You Calculate Spring Constant and Mass for Oscillations?

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SUMMARY

The spring constant (k) for a spring elongating 3 cm under a 200 g mass is calculated to be 65.4 N/m using the formula k=mg/x. The unknown mass attached to the same spring, which oscillates with a period of 3 seconds, is determined to be 14.91 kg by rearranging the equation T=2π√(m/k). The calculations confirm that the final mass value is directly in kilograms without the need for further conversion.

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  • Understanding of Hooke's Law and spring constants
  • Familiarity with the formula for the period of oscillation
  • Basic knowledge of unit conversions (grams to kilograms, centimeters to meters)
  • Ability to manipulate algebraic equations
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  • Study the derivation of Hooke's Law and its applications in mechanics
  • Learn about the relationship between mass, spring constant, and oscillation periods
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dynamity
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Homework Statement



A 200 g mass elongates a spring 3 cm from its equilibrium position. Find the spring constant (k) of the spring in N/m.

An unknown mass is attached to the same spring and set in motion. If the period of oscillation is 3 seconds, find the value of the unknown mass in kg.

Homework Equations



k=mg/x
T=2pi(sqrt)(m/k)

The Attempt at a Solution



I think I've determined part A to be 65.4 N/m. I did this by converting cm->m and g->kg. Then I filled it into the equation...

k=.2(9.81)/.03 = 65.4 N/m

Then I plug it into the other equation for part two of the question

3=2pi(sqrt)m/65.4
3/2pi (changed to .477 for ease)=sqrt(m/65.4)
.477^2=(m/65.4)
.22797=m/65.4
.22797(65.4)=m
m=14.91 kg

Mostly what I'm asking for here is a confirmation on my work and if the m at the end of my second equation comes directly in kg or if it needs to be converted first.
 
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Hi dynamity, welcome to PF.
Your answer is correct. Final answer is in kg. No need to convert to any thing.
 

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