How to Calculate the Atomic Mass of an Unknown Element M in MCl?

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SUMMARY

The discussion focuses on calculating the atomic mass of an unknown element M in the compound MCl, given that 0.7718 grams of MCl reacts with AgNO3 to produce 2.6091 grams of AgCl. To determine the atomic mass of M, one must first understand the stoichiometric relationship between silver (Ag) and chlorine (Cl) in AgCl. The calculation requires additional chemical data, specifically the molar masses of Ag and Cl, to establish the mass ratio and subsequently derive the atomic mass of M.

PREREQUISITES
  • Understanding of stoichiometry in chemical reactions
  • Knowledge of molar masses of silver (Ag) and chlorine (Cl)
  • Familiarity with the concept of chemical formulas and their implications
  • Ability to perform mass-to-mole conversions
NEXT STEPS
  • Research the molar mass of silver (Ag) and chlorine (Cl) for accurate calculations
  • Learn about stoichiometric ratios in chemical reactions
  • Study mass-to-mole conversion techniques in chemistry
  • Explore the principles of gravimetric analysis in determining unknown compounds
USEFUL FOR

Chemistry students, educators, and professionals involved in analytical chemistry and stoichiometric calculations will benefit from this discussion.

transgalactic
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unknown ellement called M reacts with Cl to make MCl
0.7718 gram of MCl reacts with AgNO_3 as a result we get
2.6091 gram of AgCl.
what is the atomic mass of M
??
 
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You are not supposed here to ask like that, but to show enough effort to show where you got stuck or made a mistake. However I will tell you you cannot solve this with only the data in the question, you were either given or expected to be able to access other general chemical information.

You might start with the 2.6091 gram of AgCl. I guess from the formula you know what is the ratio of Ag and Cl atoms in AgCl? Can you work out the ratio of grams of Ag and Cl? For that you need information that is not written above. Maybe you can think what you need and then where to find it. From that you may start thinking about the M.
 
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