a) Calculate the mass of F2 required to combine with N2 to produce 204 kg of NF3? b) what mass of N2 exactly combines with 25.91 mg of F2?
Equation: N2 + 3F2 ---> 2NF3 Convert 204 kg to grams 204 kg X 1000 grams = 204,000 grams atomic mass of N = 14.0067 u atomic mass of F = 18.998403 u
The Attempt at a Solution
I am not sure where to start. What is known: 204 kg of NF3, what is unknown: mass of F2, mass of N2
From the equation, there are 3 moles of F2, 1 mole of N2, and 2 moles of NF3
I can multiply the atomic mass of F (((18.998403 times 3) + atomic mass of N = 14.0067)) = 56.995 + 14.007 to get 71.002 grams of NF3