How to Calculate the Bounces of a Bouncy Ball

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To calculate the height of a bouncy ball's bounce, consider the mass, height, and gravity, but also note that the coefficient of restitution is crucial for accurate results. Without additional factors, a ball will theoretically bounce back to its original height indefinitely. For practical experimentation, users are advised to bounce a ball on a surface and record the maximum height after each bounce to gather data. This method allows for data fitting to refine the calculations. Understanding these principles will aid in developing the code needed for the project.
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Homework Statement
If I were to say M was mass, H was height, and G was gravity, what equation could I plug those variables into to get how high and how many times a ball would bounce after being dropped.
Relevant Equations
Mass, Gravity, and Height of ball being dropped
For school I'm trying to write some code to calculate the height of how high a ball would bounce given its mass, height, and the gravity of where it was dropped. I know there are more variables to consider, like wind resistance and the surface it was dropped on, but for now I'm trying to keep it simple.
"If I were to say M was mass, H was height, and G was gravity, what equation could I plug those variables into to get how high and how many times a ball would bounce after being dropped."
Sorry if any of this seems unclear, I know almost nothing about physics but I need to figure this out for my computer science class.
 
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Without additional assumptions the ball will bounce back to its original height indefinitely.
 
Look up coefficient of restitution.
 
Why not get yourself a bouncy ball, bounce it off the floor with some kind of scale behind it and take a video. You can estimate the maximum height after each bounce and then write the code to describe the motion. It's called data fitting. As a @harusex PF user @haruspex suggested, look up coefficient of restitution.
 
Last edited:
kuruman said:
As a @harusex
Something else on your mind?
 
haruspex said:
Something else on your mind?
Oooops, just one of them Freudian slips. :blushing:
 
Thread 'Chain falling out of a horizontal tube onto a table'
My attempt: Initial total M.E = PE of hanging part + PE of part of chain in the tube. I've considered the table as to be at zero of PE. PE of hanging part = ##\frac{1}{2} \frac{m}{l}gh^{2}##. PE of part in the tube = ##\frac{m}{l}(l - h)gh##. Final ME = ##\frac{1}{2}\frac{m}{l}gh^{2}## + ##\frac{1}{2}\frac{m}{l}hv^{2}##. Since Initial ME = Final ME. Therefore, ##\frac{1}{2}\frac{m}{l}hv^{2}## = ##\frac{m}{l}(l-h)gh##. Solving this gives: ## v = \sqrt{2g(l-h)}##. But the answer in the book...

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