How to calculate the comet's speed?

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To calculate the speed of Comet Halley as it crosses Neptune's orbit, the conservation of energy equation K2 + U2 = K1 + U1 is applied, where the mass of the comet is not necessary for the calculation. The mass used in the potential energy terms is the mass of the sun, as the comet orbits around it. Kepler's laws can help determine the mass of the sun, but the mass of Neptune is irrelevant in this context. The discussion emphasizes that for similar orbital problems, the mass involved will typically be that of the central body, which is the sun in this case. Understanding these principles allows for accurate calculations of celestial object speeds in elliptical orbits.
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Homework Statement



Comet moves around the sun in a very ellipical orbit around the sun. As it approach, in 1986, Comet Halley was 8.79x10^7km from the sun and moving with a speed of 54.6km/s. What will be the comet's speed be when it crosses Neptune's orbit in 2006?

length of comet from the sun = 8.79x10^7km = 8.79x10^10 m
v of comet = 54.6km/s = 54.6x10^3m/s
T = 20 years
length of neptune from the sun = 4.50x10^12m


Homework Equations



i use the equation T^2 = (4*pie*r^3)/GM and K2 + U2 = K1 + U1

The Attempt at a Solution


i first use the Kelper's rule to find M of the comet, but i don't really know if that's the right step to start with.

Thank you.
 
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Make the substitutions in your conservation of energy equation and see if you really need to know the mass of the comet.
 
one question, when we calculate with the K2 + U2 = K1 + U1, the M we are using, is that the mass of the sun or neptune?
 
jkh4 said:
one question, when we calculate with the K2 + U2 = K1 + U1, the M we are using, is that the mass of the sun or neptune?

The mass of Neptune does not matter. You are just using the radius of the Neptune orbit as a distance from the sun. The potential energy terms depend on the mass of the sun and the mass of the comet.
 
i got the answer, thank you so much!

btw, so does that mean if for similar questions, the M is always M of sun?
 
Last edited:
jkh4 said:
i got the answer, thank you so much!

btw, so does that mean if for similar questions, the M is always M of sun?

If the orbit is an orbit around the sun, then the mass of the sun is involved. There are many problems involving orbits around other force centers, so M will not always be the sun's mass.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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