How to calculate the enthelpy change of a neutralization reaction

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To calculate the enthalpy change of a neutralization reaction, such as between NaOH and HCl, the formula used is delta H = [products] - [reactants]. The enthalpy of neutralization for a strong acid and strong base is typically around -13.7 Kcal. However, calculations can vary based on data sources, with one example yielding -43 Kcal/mol. Accurate calculations require knowledge of the enthalpy of formation for each compound involved. Starting from standard elements in their most stable state is essential for precise results.
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Hi. I would very much like to know how to calculate the enthalpy change of a neutralization reaction, for example, NaOH(aq) and HCl(aq).
Thank you very much.
 
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stargazer said:
Hi. I would very much like to know how to calculate the enthalpy change of a neutralization reaction, for example, NaOH(aq) and HCl(aq).
Thank you very much.

Strong acid + strong base has an enthalpy of neutrailzation = -13.7 Kcal

which is the case here
 
Start from the standard elements in their most stable state at standard conditions. Unless the enthalpy of formation for each compound is provided to you already, it can be a bit complex. Here is an example...

http://groups.msn.com/GeneralChemistryHomework/general.msnw?action=get_message&mview=0&ID_Message=116&LastModified=4675466454162512526
 
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The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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