How to calculate the time for one revolution in circular motion?

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SUMMARY

The discussion focuses on calculating the time for one revolution of a mass attached to a string in circular motion. The mass is 10 kg, the string length is 0.027 m, and the angle with the vertical is 32 degrees. Key equations include the radius calculation using Lsin(angle) and the relationship between velocity, period, and radius defined by v=2π(r)/T. Participants clarify the use of angles and tension in the equations to derive the period of revolution accurately.

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Homework Statement


The mass m = 10 kg and is attached to a string L = 0.027m, the mass moves in a circle and makes an angle of 32 deg. with the vertical, how long does it take to complete one revolution?


Homework Equations



radius = Lsin(angle)
v=2pi(r)/T
F= max (where F = Tx = -Ty)
-Ty = m(v^2/r)

The Attempt at a Solution


I tried solving for velocity with T = 1, is this right?
If the angle is wrt the vertical, does that mean I have to take 90 - the angle, inorder to change it wrt the horizontal and then use that angle to solve for radius?
Any help would be great. Thanks.

 
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What do you mean T = 1? Do you mean T as the period or the tension?
Yes, 90 - angle of vertical = angle from horizontal.

You say F = Tx = -Ty

Is T tension?
Why does Tx = -Ty?
 
T is the period
I was going to use -Ty to solve the equation if I do not change the angle
but so far I have tried to use the equation Fnet = ma
Fnet = Tsin angle = ma
a = v^2/r
r = Lsin angle
Tsin (angle) = m (v^2)/r(sin angle)^2 is this right?
 

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