How to Calculate Time Period and Frequency?

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Discussion Overview

The discussion revolves around the concepts of time period and frequency in the context of a pendulum, including how these concepts apply when considering a pendulum on the Moon. Participants seek to clarify definitions, formulas, and the effects of gravitational differences on pendulum behavior.

Discussion Character

  • Exploratory
  • Technical explanation
  • Debate/contested
  • Mathematical reasoning

Main Points Raised

  • Some participants define the time period of a seconds pendulum as 2 seconds and express confusion about the corresponding frequency.
  • One participant suggests that understanding the definitions of time period and frequency could resolve the problem without relying solely on formulas.
  • There is a discussion about the formula for frequency, f = 1/t, with some participants questioning the units involved.
  • Concerns are raised about the implications of moving a pendulum to the Moon, with one participant suggesting that the time period would decrease due to an inverse relationship with gravitational acceleration.
  • Another participant questions the correctness of the unit for frequency, with discussions about whether it is expressed as s^-1 or Hertz (Hz).
  • There is a disagreement regarding whether the period of the pendulum will become longer or shorter when moved to the Moon.
  • Participants inquire about the specific formula for calculating the period of a pendulum and which values are constant versus changing when transitioning from Earth to the Moon.

Areas of Agreement / Disagreement

Participants express differing views on the effects of moving a pendulum to the Moon, particularly regarding whether the time period will increase or decrease. There is no consensus on the correct unit for frequency or the specific formula for pendulum period calculation.

Contextual Notes

Participants have not fully resolved the implications of gravitational differences on pendulum behavior, and there are uncertainties regarding the definitions and units for time period and frequency.

r-soy
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A sconds pendulum taks 1 s to move from one extreme to the other

what is time period ?
what is frequency ?




what is the formula to use when found to time period and frequency the formula not written in our note
 
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see... if you can define time period and frequency ... well, your problem would be solved!

You don't need formulas for everything... sometimes you got to make them on your own...meaning every formula can't be stuffed into any book... many change according to the given problem.
 


I try ,,,,

what is time period ?

it's = 2s

what is frequency ?

but the solving frequency by formula

please hlep me .
 


what kinda english is that?

anyway, your time period is right and
f=1/t
 


The legend said:
what kinda english is that?

Probably non-native.
 


my language is not english

anyway, f=1/t that mean 1/1 = 1 but the unit should be what ?

what happen to the time period if you take your pendulum to the moon ?

please I want your help

thanks
 


r-soy said:
anyway, f=1/t that mean 1/1 = 1 but the unit should be what ?

What is unit of t? Take a look at the equation - what unit do you get from calculations?

what happen to the time period if you take your pendulum to the moon ?

Do you know any formula describing pendulum period?
 


Borek said:
What is unit of t? Take a look at the equation - what unit do you get from calculations?


i think the answe is 1s^-a are this uint and answe correct .
Do you know any formula describing pendulum period?

what happen to the time period if you take your pendulum to the moon ?

my answer is when we increase the pendulum the time period will decrease
because there is inverse relation between time and acceleration of gravity
help me
 
Last edited:


Borek where are you ?
 
  • #10


I think I told you I have a life outside PF? I am playing Fallout 3 if you are really interested.

r-soy said:
i think the answe is 1s^-a are this uint and answe correct .

s-a - I have no idea what you mean by a, so I have no idea whether you are right or not.

r-soy said:
my answer is when we increase the pendulum the time period will decrease because there is inverse relation between time and acceleration of gravity

Question was not about "increasing the pendulum" (whatever it should mean), but about moving it to the Moon. There is a grain of truth in your thinking - period of pendulum will change because gravitational attraction on the Moon surface differs from the attraction on the Earth surface.
 
  • #11


sorry i mean s^-1 is this correct .

about (period of pendulum) will change because gravitational attraction on the Moon surface differs from the attraction on the Earth surface.

here (period of pendulum) or (period of time )
 
  • #12


s-1 is correct. This unit has its own name - Hertz (Hz).

OK, period of pendulum will change - but will it get longer, or shorter?
 
  • #13


it will come shorter
 
  • #14


^^ i don't think so...
 
  • #15


What is the formula used for period calculation, which values are constant and which are changing when you move from the Earth to Moon?
 

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