Period of a Pendulum on the Moon

  • #1
Homework Statement
I need help and clarification about "Period of Pendulum on the moon"
Relevant Equations
The equation that governs the period of a pendulum’s swinging. T=2π√L/g

Where T is the period, L is the length of the pendulum and g is a constant, equal to 9.8 m/s2. The symbol g is a measure of the strength of Earth’s gravity, and has a different value on other planets and moons.

On our Moon, the strength of earth’s gravity is only 1/6th of the normal value. If a pendulum on Earth has a period of 4.9 seconds, what is the period of that same pendulum on the moon?
  • #2
What specific question do you have?
  • #3
I am getting 12 as an answer when the right answer is 2
  • #4
Please show your work then. We can't tell where your mistake lies if we can't see what you did. Also, don't forget the units.
  • #5
I think you are right. It is clear from the equation that if g is smaller, T must be greater.
Tm/Te = √(ge/gm)
I think "they" have mistakenly multiplied the period by √(gm/ge).
  • #6

T = 4.9 g = 9.8

g = (T/2 π)2 = L

9.8 (9.8/2 π)2 = 5.96 = L

T = 2 π √L/g

12 = 2 π √5.96/1.64
  • #7
Other than the lack of units and a few obvious typos, your work looks fine. As @mjc123 points out, you should expect from the formula the period to increase as ##g## decreases. Intuitively, if the weight of the mass decreases, the restoring torque decreases as well, so you would expect it to take longer to oscillate.
  • #8
Thank you for your help and clarification.

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