# Period of a Pendulum on the Moon

## Homework Statement:

I need help and clarification about "Period of Pendulum on the moon"

## Relevant Equations:

T=2π√L/g
The equation that governs the period of a pendulum’s swinging. T=2π√L/g

Where T is the period, L is the length of the pendulum and g is a constant, equal to 9.8 m/s2. The symbol g is a measure of the strength of Earth’s gravity, and has a different value on other planets and moons.

On our Moon, the strength of earth’s gravity is only 1/6th of the normal value. If a pendulum on Earth has a period of 4.9 seconds, what is the period of that same pendulum on the moon?

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vela
Staff Emeritus
Homework Helper
What specific question do you have?

I am getting 12 as an answer when the right answer is 2

vela
Staff Emeritus
Homework Helper
Please show your work then. We can't tell where your mistake lies if we can't see what you did. Also, don't forget the units.

mjc123
Homework Helper
I think you are right. It is clear from the equation that if g is smaller, T must be greater.
Tm/Te = √(ge/gm)
I think "they" have mistakenly multiplied the period by √(gm/ge).

vela
T=2π√L/g

T = 4.9 g = 9.8

g = (T/2 π)2 = L

9.8 (9.8/2 π)2 = 5.96 = L

T = 2 π √L/g

12 = 2 π √5.96/1.64

vela
Staff Emeritus