High School How to calculate time with delta-v and velocity?

[alberto91]

Is this correct?

Why the time is minutes instead of seconds?

Thanks!

 

[WWGD]

By dimensional analysis your t has no units.

 

[alberto91]

By dimensional analysis your t has no units.

And how can I calculate that equation?

 

[WWGD]

What I mean is you're dividing two expressions with m/s as units, which cancel out. This tells you you're doing something wrong somewhere. I guess you want to use t=d/v? Then d is given in meters ( or another unit of distance) . In your case you used 1 m/s , which is not a measure of distance.

 

[alberto91]

What I mean is you're dividing two expressions with m/s as units, which cancel out. This tells you you're doing something wrong somewhere. I guess you want to use t=d/v? Then d is given in meters ( or another unit of distance) . In your case you used 1 m/s , which is not a measure of distance.

Thanks for your answer.

I want to use delta-vee (dv)

 

[mfig]

To find the time you need a relationship between velocity and time such as the definition of acceleration:

$\frac{dv}{dt}=a$

Then separate and integrate:

$dv=adt \rightarrow \int_{0}^{v_{needed}} dv = \int_{0}^{t_{needed}}a dt$

This gives

$v_{needed} = at_{needed}$

So to find the time needed to get to the needed velocity, simply divide.

$t_{needed} = v_{needed}/a$

Note that this assumes constant acceleration from zero. So it seems the solution you showed has the wrong units for acceleration.

 

[mfb]

There is context missing. Do you have a constant acceleration? If yes, what is its value? Maybe 0.2636 m/(s*min)?