How to Choose Resistors for Desired Currents in a Circuit

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Homework Help Overview

The discussion revolves around selecting resistor values in a circuit to achieve specified currents through parallel branches, with a voltage constraint of less than 2.5 V.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants explore the relationship between voltage, current, and resistance using Ohm's Law and discuss the implications of choosing different voltage values for the circuit.

Discussion Status

Some participants have provided guidance on simplifying the problem by selecting a specific voltage and resistor values to calculate the required resistances. There is an acknowledgment of the ability to scale resistances if a higher voltage is needed.

Contextual Notes

Participants are working under the constraint that the voltage must be less than 2.5 V and are considering the implications of this limit on their calculations.

Mosaness
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1.Choose a voltage v < 2.5 V and values for the resistors R1, R2, R3, and R4 in
the circuit of Fig. 3.90 so that i1 =1 A, i2 =1.2 A, i3 =8 A, and i4 = 3.1 A.




Homework Equations



KCL/KVL/OHms Law



The Attempt at a Solution



If Is = I1 + I2 + I3 + I4,

Then, Is = [itex]\frac{v}{R<sub>eq</sub>}[/itex]

Req = [itex]\frac{1}{R<sub>1</sub>}[/itex] + [itex]\frac{1}{R<sub>2</sub>}[/itex] + [itex]\frac{1}{R<sub>3</sub>}[/itex] + [itex]\frac{1}{R<sub>4</sub>}[/itex].

After this, I get stuck...
 

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You're over thinking the problem. For parallel branches, the voltage is the same to all branches of the node. For simplicity choose 1V and for R1 choose 1 ohm so that I1 = 1A. Now you have the voltage and current for each branch so just solve for resistance via ohm's law.
 
Bhumble said:
You're over thinking the problem. For parallel branches, the voltage is the same to all branches of the node. For simplicity choose 1V and for R1 choose 1 ohm so that I1 = 1A. Now you have the voltage and current for each branch so just solve for resistance via ohm's law.

So because we can choose any v that is less than 2.5V, you picked 1V correct?
 
Taking V as 1A and using the given values for the currents, I solved for R1, R2, R3, and R4:

R1 = 1V/1A = 1Ω

R2 = 1V/1.2A = 0.83Ω

R3 = 1V/8A = 0.125Ω

R4 = 1V/3.1A = 0.323Ω

Is this correct?
 
Looks good. And if for some reason you need the voltage to be higher than you can just scale the resistance proportionately to maintain the same current.
 

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