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How to compute the magnitude of a initial velocity u

  • Thread starter javii
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1. Homework Statement
A rock is thrown horizontally from a tower point A, and hits the ground 3.5 s later at point B. A line from A to B makes an angle of 50 degrees with the horizontal.
Compute the magnitude of a initial velocity u of the rock.

3. The Attempt at a Solution
I started looking at the motion in x direction, which is
u the unknown.
Then i looked at the motion in y direction:
And here we have the gravity.
so i used the formula:
s=1/2 * g * t^2

1/2*9.81*(3.5)^2 =60 m/s^2

from trigonometry

tan(50)=60/x
solving x i get 50.34 meters

But I'm not sure if I have done it corretly.

Thank you for your help.
 

kuruman

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1/2*9.81*(3.5)^2 =60 m/s^2
The units should be meters. Other than that, so far you are on the right track, but you have not answered the question yet. You found where the rock lands horizontally, but you are asked to find its initial speed.
 

cnh1995

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The units should be meters. Other than that, so far you are on the right track, but you have not answered the question yet. You found where the rock lands horizontally, but you are asked to find its initial speed.
That's right. But you need to find the x component of the velocity.
The units should be meters. Other than that, so far you are on the right track, but you have not answered the question yet. You found where the rock lands horizontally, but you are asked to find its initial speed.
aha, so I have to times the denominator with the time (3.5):

tan(50)=60/x*3.5
Then I will get
14.38 m/s

It that true?
 

kuruman

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That is the correct answer. However it is more conventional to divide (untimes) the distance by the time to get the speed. :smile:
 
23
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That is the correct answer. However it is more conventional to divide (untimes) the distance by the time to get the speed. :smile:
haha, i will remember that for next time :) Thank you for your time. :)
 

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