How to Convert 938.3 MeV/c² to Kilograms?

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SUMMARY

The conversion of 938.3 MeV/c² to kilograms involves using the relationship between electron volts and joules. Specifically, 1 eV is equivalent to 1.602 x 10^(-19) joules. To convert MeV to joules, multiply by 1,000 (since 1 MeV = 1,000 eV). The final conversion to kilograms is achieved by applying the formula 1 eV/c² = (1.602 x 10^(-19) J) / (c²), where c is the speed of light in m/s.

PREREQUISITES
  • Understanding of energy units, specifically electron volts (eV) and joules (J).
  • Familiarity with the speed of light (c) and its value in meters per second (m/s).
  • Basic knowledge of dimensional analysis and unit conversion.
  • Concept of mass-energy equivalence as described by Einstein's equation E=mc².
NEXT STEPS
  • Research the conversion factors between MeV and joules in detail.
  • Learn about the implications of mass-energy equivalence in physics.
  • Explore dimensional analysis techniques for unit conversions.
  • Study the speed of light and its significance in relativistic physics.
USEFUL FOR

Students in physics, particularly those studying particle physics or energy-mass relationships, as well as educators teaching unit conversions in scientific contexts.

cragar
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Homework Statement


how do i convert 938.3MeV/(c^2) to kilo grams

The Attempt at a Solution



so this is mega electron volts divided by c^2 do i just divide it by 1.602*10^(-19) joules
is e measured in coulombs and a volt is a joule per coulomb.
 
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The eV is a measure of energy, equalling somewhere about 1.6 * 10^(-19) J
1 J = 1 kg * m^2/s^2
I assume c wants to be the speed of the light, which is given in m/s

so 1 eV/c^2= (some scalar) * kg * m^2/s^2 / (m/s)^2
now what you get by simplifying?

It always helps not to forget to write the units, and go for base units when in doubt.
 
thanks , ok i see , so i multiply it by 1.602*10^(-19)J/1eV to get it Kg .
correct
 

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