How to Convert Tartaric Acid to H2C2O4?

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SUMMARY

The discussion focuses on the conversion of tartaric acid to oxalic acid, specifically identifying tartaric acid as 2,3-dihydroxybutanedioic acid. Participants clarify that oxalic acid is a dicarboxylic acid, while tartaric acid is a 2,3-dihydroxy-1,4-dicarboxylic acid. The use of dilute KMnO4 is highlighted as a method to differentiate between these compounds, with oxalic acid yielding a positive result through decoupling of purple KMnO4. The correct nomenclature for tartaric acid is emphasized, correcting common misconceptions.

PREREQUISITES
  • Understanding of organic chemistry nomenclature
  • Knowledge of dicarboxylic acids
  • Familiarity with oxidation-reduction reactions
  • Experience with chemical testing methods, specifically using KMnO4
NEXT STEPS
  • Research the structural formulas of dicarboxylic acids
  • Learn about the oxidation reactions involving KMnO4
  • Study the nomenclature rules for organic compounds
  • Explore the properties and applications of oxalic acid in organic synthesis
USEFUL FOR

Chemistry students, organic chemists, and educators seeking to deepen their understanding of acid conversions and chemical nomenclature.

desmond iking
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Homework Statement


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The Attempt at a Solution


i need ans for this whole question . my ans for part i ) is oxalic acid - dicarboxlic acid tartaric acid - 2,3-dihydroxo-1,4-dicarboxlic acid .

for part c ) I used dilute KMNO4 to differentiate these 2 compounds . Oxalic acid will show positive result , which is CO2 ANH H20 formed , and purple KMON4 decoulorises.
 

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desmond iking said:
i need ans for this whole question

Then try to answer it. Asking four question and answering two of them to pretend you attempted to solve won't work.

Your names are wrong. 30 seconds googling to find the correct ones on the web.
 
Borek said:
ogling to find the correct ones on t
well , the ans for tartraic acid acid is 2,3-dihydroxybutanedioic acid... i am wondering why not 2,3-dihydroxy-1,4-butanedioic acid... Why the 1, 4 is not needed?
 
Borek said:
Then try to answer it. Asking four question and answering two of them to pretend you attempted to solve won't work.

Your names are wrong. 30 seconds googling to find the correct ones on the web.
i am just having problem with the two of the question , NOT ALL...
 

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