How to deal with learning plateau in CS?

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Reaching a learning plateau can be frustrating, but several strategies can help overcome it. Engaging with a structured course from a knowledgeable instructor can provide new insights and direction. Reading material aloud can enhance comprehension and retention. Deliberate practice, which involves repetitive engagement with the same concepts, can deepen understanding and facilitate breakthroughs. Additionally, applying theoretical knowledge to practical problems, such as coding challenges in machine learning, can stimulate learning. For instance, tackling arithmetic equations where letters represent digits requires logical reasoning and algorithmic implementation. Constructing loops to explore digit combinations while adhering to constraints can lead to effective problem-solving and reinforce learning. Optimizing the search process by eliminating impossible scenarios can further enhance efficiency and understanding.
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Summary:: learning plateau

I have reached a place where I can no more learn new concepts. I feel totally stuck.How do I deal with learning plateau? How do I overcome this plateau. Few things that come in my mind-:

1) Follow a good course from a good teacher.

2) Read it aloud.

3) Practice the same thing multiple things to get insights. deliberate practice

What else can I do to overcome this learning plateau? These are the types of questions I need to deal with and where I am facing this learning plateau..
 
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I suggest that you write some code.
 
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Many ML problems rely on on search methods to find an answer. Look at the questions, think of how you would solve it on paper and then try to implement an algorithm to solve.

As an example, problem 2 asks you to find a solution to a arithmetic equation where letters represent digits. The first thing to note is that LOG letters/digits are found on both sides and so are the constraints you need to keep in mind. The second fact is that L, O, and G and the other letters represent different digits.

From there you can construct, FOR loops for L, O, and G to search for possible digit combinations while varying the I, C, P, and R choices.

2*(10000*L + 1000*O + 100*G + 10*I + C) = 100000*P + 10000*R + 1000*O + 100*L + 10*O + G

This is only a first attack then you might notice some optimizations you can apply to speed up the search like maybe P and L can't be zero. Not during the nested FOR loops would L equal O or G so when that happens you can skip that iteration.
 
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