How to Deduce the Normal Vector from a Given Vector Equation?

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SUMMARY

The discussion centers on deducing the normal vector from the vector equation of a plane. The provided vector equation is r = (1/2, 1, 2/3) + t(3/2, 2, -2/3). The correct normal vector derived from this equation is (9, 12, -4). The method involves multiplying the direction vector (3/2, 2, -2/3) by 6 to eliminate the fractions, leading to the final normal vector.

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acpower89
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I'm having trouble finding the equation normal to the plane for part (ii).

The vector equation I got for part (i) is r=(1/2,1,2/3) + t(3/2,2,-2/3). How do you deduce the normal vector from this? The answer is the vector (9,12,-4). I've tried anything but don't know where they got this result.

Thanks
 

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They used your (3/2,2,-2/3) and multiplied by 6 to clear the denominator.
 

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