How to define a set without set builder notation

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SUMMARY

The discussion clarifies that defining a set without set-builder notation is valid and equivalent to using it. For instance, the set S defined as S={1,2,3,4} can also be expressed using logical predicates, such as ∀x(x ∈ ℕ ^ 0 PREREQUISITES

  • Understanding of set theory concepts, particularly set notation.
  • Familiarity with logical predicates and their use in mathematics.
  • Basic knowledge of isomorphism in algebraic structures.
  • Awareness of Russell's paradox and its implications in set theory.
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  • Explore the principles of set theory and its notation in detail.
  • Study logical predicates and their applications in defining mathematical sets.
  • Investigate the isomorphism between set algebra and boolean algebra.
  • Learn about Russell's paradox and its impact on set theory formulations.
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Mathematicians, educators, and students interested in advanced set theory concepts and logical reasoning in mathematics.

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How do you define a set without using set builder notation? For example, let's say that I want to define set S as:

S={x ∈ ℕ ∣ 0<x<5}

Then
S={1,2,3,4}
However, suppose that I wanted to define S without set-builder notation, as below?

∀x(x ∈ ℕ ^ 0<x<5 ⟺ x∈S )

Would these two statements be equivalent, or is there something else provided in the set builder notation that I am missing?

Thanks.
 
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The two statements are completely equivalent.
 
Your definition is fine. In essence a set is isomorphic to the logical predicate defining which elements are in the set. Set algebra and boolean algebra are isomorphic. (This is true provided we forbid self reference in predicates which would allow formulation of a Russell's paradox.)

So for example {} = X such that for all a in X, True=False. (there is thus never an a in X).

We typically do the reverse however. We like to map logic into set notation and set concepts. See for example introductory probability theory.
 

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