How to Derive the Continuity Equation for a Particle in a 1D Potential?

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The discussion focuses on deriving the continuity equation for a particle in a 1D potential using the time-dependent Schrödinger equation. Participants address the calculation of the probability density and current density, emphasizing the need for correct differentiation and complex conjugation in the expression for current density. There is clarification that solving the Schrödinger equation is not necessary to find the probability density, and suggestions are made to use the equation to replace time derivatives of the wavefunction. The conversation highlights common mistakes in calculus and encourages participants to correct their approaches. Overall, the thread provides guidance on the mathematical techniques required to derive the continuity equation.
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Homework Statement


There's a particle moving in a 1D potential V(x) with mass m. The particle's normalised wavefunction is ψ(x,t). Use the time dependent Schrodinger equation to show that ##\frac{\partial{\rho}}{\partial{t}} + \frac{\partial{j}}{\partial{x}} = 0##
Where
##j(x,t) = -\frac{i\hbar}{2m}(\psi^{*} \frac{\partial{\psi}}{\partial{x}} - \psi \frac{\partial{\psi}}{\partial{x}})##

I also have to show that j(x,t) is real. All I know about j is that it has to be equal to the magnitude of ψ(x,t)##^{2}##.

Homework Equations


Time dependent Schrodinger equation:
##i\hbar \frac{\partial{\psi}}{\partial{t}} = -\frac{\hbar^{2}}{2m} \frac{\partial^{2}{\psi}}{\partial{x^2}} + V(x) \psi##

The probability density ρ = |ψ(x,t)|^2 or ψψ*.

The Attempt at a Solution


I'm having a bit of trouble with the calculus element. Pretty sure I'm differentiating wrong AND integrating wrong, but anyway, here's what I got:
First I thought I'd calculate ##\frac{\partial{j}}{\partial{x}}## since j is given. I got
##-\frac{i\hbar}{2m}(\psi^{*}\frac{\partial^{2}{\psi}}{\partial{x^2}}+\frac{\partial{\psi}}{\partial{x^2}}\psi^{*}-\psi\frac{\partial^{2}{\psi^{*}}}{\partial{x^2}}+\frac{\partial{\psi}}{\partial{x}}\frac{\partial{\psi}}{\partial{x}})##.

Then I thought I would solve the Schrodinger equation. But (and I know this isn't exactly a good reason) the question is only worth five marks! Which makes me think that I might not have to solve the Schrodinger equation. And I wouldn't actually know how to solve it anyway...

So is my first calculation right? And do I need to solve the Schrodinger equation in order to answer this question? If I do... how do I do it??
 
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whatisreality said:
Then I thought I would solve the Schrodinger equation.
Why do you think solving the Schrodinger equation would be useful? Besides, it is not possible to solve the Schrodinger equation in closed form for general V(x)

There is a mistake in your expression for the current density. There should be a complex conjugation on the second term: j(x,t) \equiv -\frac{i\hbar}{2m} \left(\psi^{*} \partial_{x} \psi - \psi \partial_{x} \psi^{*} \right)
Calculating \partial_{x} j(x,t) is a good place to start - do correct the complex conjugation mistakes though.
Have you tried calculating \partial_{t} \rho?
 
Fightfish said:
Why do you think solving the Schrodinger equation would be useful? Besides, it is not possible to solve the Schrodinger equation in closed form for general V(x)

There is a mistake in your expression for the current density. There should be a complex conjugation on the second term: j(x,t) \equiv -\frac{i\hbar}{2m} \left(\psi^{*} \partial_{x} \psi - \psi \partial_{x} \psi^{*} \right)
Calculating \partial_{x} j(x,t) is a good place to start - do correct the complex conjugation mistakes though.
Have you tried calculating \partial_{t} \rho?
So it represents current density! Interesting. OK, I'll sort out the conjugation mistakes - if I add the *, should it be correctly differentiated though?

I have tried calculating ρ for a start, but pretty unsuccessfully. I think I broke some rules along the way, while trying to solve the schrodinger equation, the potential was still in the equation at the end. I'll post where I got to...
 
So corrected version for partial derivative of j: ##-\frac{i\hbar}{2m}(\psi^{*}\frac{\partial^{2}{\psi}}{\partial{x^2}}+\frac{\partial{\psi^{*}}}{\partial{x}}\frac{\partial{\psi}}{\partial{x}}-\psi\frac{\partial^{2}{\psi^{*}}}{\partial{x^2}}-\frac{\partial{\psi}}{\partial{x}}\frac{\partial{\psi^{*}}}{\partial{x}})##
 
Fightfish said:
Why do you think solving the Schrodinger equation would be useful? Besides, it is not possible to solve the Schrodinger equation in closed form for general V(x)

There is a mistake in your expression for the current density. There should be a complex conjugation on the second term: j(x,t) \equiv -\frac{i\hbar}{2m} \left(\psi^{*} \partial_{x} \psi - \psi \partial_{x} \psi^{*} \right)
Calculating \partial_{x} j(x,t) is a good place to start - do correct the complex conjugation mistakes though.
Have you tried calculating \partial_{t} \rho?
As for ##\rho##, actually I know my method was wrong. I made ∂Ψ/∂t the subject and then integrated. I don't know how to solve the Schrodinger equation, so I can't find ##\rho##.
 
You don't need to solve the Schrodinger equation to "find" \rho.
\partial_{t} (\psi^{*}\psi) = \psi \partial_{t} \psi^{*} + \psi^{*} \partial_{t} \psi
Now, use the Schrodinger equation to replace \partial_{t} \psi^{*} and \partial_{t} \psi
 
Fightfish said:
You don't need to solve the Schrodinger equation to "find" \rho.
\partial_{t} (\psi^{*}\psi) = \psi \partial_{t} \psi^{*} + \psi^{*} \partial_{t} \psi
Now, use the Schrodinger equation to replace \partial_{t} \psi^{*} and \partial_{t} \psi
Got it, thank you!
 

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