How to Derive the Continuity Equation for a Particle in a 1D Potential?

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Homework Help Overview

The discussion revolves around deriving the continuity equation for a particle in a one-dimensional potential using the time-dependent Schrödinger equation. The original poster attempts to show that the equation ##\frac{\partial{\rho}}{\partial{t}} + \frac{\partial{j}}{\partial{x}} = 0## holds true, where ##j(x,t)## represents the current density associated with the wavefunction ##\psi(x,t)##.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants explore the relationship between the wavefunction and the continuity equation, with some questioning the necessity of solving the Schrödinger equation. There are discussions about the correct formulation of the current density and the implications of complex conjugation. The original poster expresses uncertainty about their differentiation and integration skills.

Discussion Status

Participants are actively engaging with the problem, providing corrections and suggestions for the original poster's calculations. There is a focus on ensuring the correct formulation of the current density and exploring how to calculate the time derivative of the probability density. Some guidance has been offered regarding the use of the Schrödinger equation without needing to solve it explicitly.

Contextual Notes

There is an acknowledgment of potential misunderstandings regarding the application of the Schrödinger equation and the rules of differentiation and integration. The original poster mentions feeling constrained by the problem's mark allocation, which may influence their approach.

whatisreality
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Homework Statement


There's a particle moving in a 1D potential V(x) with mass m. The particle's normalised wavefunction is ψ(x,t). Use the time dependent Schrödinger equation to show that ##\frac{\partial{\rho}}{\partial{t}} + \frac{\partial{j}}{\partial{x}} = 0##
Where
##j(x,t) = -\frac{i\hbar}{2m}(\psi^{*} \frac{\partial{\psi}}{\partial{x}} - \psi \frac{\partial{\psi}}{\partial{x}})##

I also have to show that j(x,t) is real. All I know about j is that it has to be equal to the magnitude of ψ(x,t)##^{2}##.

Homework Equations


Time dependent Schrödinger equation:
##i\hbar \frac{\partial{\psi}}{\partial{t}} = -\frac{\hbar^{2}}{2m} \frac{\partial^{2}{\psi}}{\partial{x^2}} + V(x) \psi##

The probability density ρ = |ψ(x,t)|^2 or ψψ*.

The Attempt at a Solution


I'm having a bit of trouble with the calculus element. Pretty sure I'm differentiating wrong AND integrating wrong, but anyway, here's what I got:
First I thought I'd calculate ##\frac{\partial{j}}{\partial{x}}## since j is given. I got
##-\frac{i\hbar}{2m}(\psi^{*}\frac{\partial^{2}{\psi}}{\partial{x^2}}+\frac{\partial{\psi}}{\partial{x^2}}\psi^{*}-\psi\frac{\partial^{2}{\psi^{*}}}{\partial{x^2}}+\frac{\partial{\psi}}{\partial{x}}\frac{\partial{\psi}}{\partial{x}})##.

Then I thought I would solve the Schrödinger equation. But (and I know this isn't exactly a good reason) the question is only worth five marks! Which makes me think that I might not have to solve the Schrödinger equation. And I wouldn't actually know how to solve it anyway...

So is my first calculation right? And do I need to solve the Schrödinger equation in order to answer this question? If I do... how do I do it??
 
Last edited:
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whatisreality said:
Then I thought I would solve the Schrödinger equation.
Why do you think solving the Schrödinger equation would be useful? Besides, it is not possible to solve the Schrödinger equation in closed form for general V(x)

There is a mistake in your expression for the current density. There should be a complex conjugation on the second term: j(x,t) \equiv -\frac{i\hbar}{2m} \left(\psi^{*} \partial_{x} \psi - \psi \partial_{x} \psi^{*} \right)
Calculating \partial_{x} j(x,t) is a good place to start - do correct the complex conjugation mistakes though.
Have you tried calculating \partial_{t} \rho?
 
Fightfish said:
Why do you think solving the Schrödinger equation would be useful? Besides, it is not possible to solve the Schrödinger equation in closed form for general V(x)

There is a mistake in your expression for the current density. There should be a complex conjugation on the second term: j(x,t) \equiv -\frac{i\hbar}{2m} \left(\psi^{*} \partial_{x} \psi - \psi \partial_{x} \psi^{*} \right)
Calculating \partial_{x} j(x,t) is a good place to start - do correct the complex conjugation mistakes though.
Have you tried calculating \partial_{t} \rho?
So it represents current density! Interesting. OK, I'll sort out the conjugation mistakes - if I add the *, should it be correctly differentiated though?

I have tried calculating ρ for a start, but pretty unsuccessfully. I think I broke some rules along the way, while trying to solve the Schrödinger equation, the potential was still in the equation at the end. I'll post where I got to...
 
So corrected version for partial derivative of j: ##-\frac{i\hbar}{2m}(\psi^{*}\frac{\partial^{2}{\psi}}{\partial{x^2}}+\frac{\partial{\psi^{*}}}{\partial{x}}\frac{\partial{\psi}}{\partial{x}}-\psi\frac{\partial^{2}{\psi^{*}}}{\partial{x^2}}-\frac{\partial{\psi}}{\partial{x}}\frac{\partial{\psi^{*}}}{\partial{x}})##
 
Fightfish said:
Why do you think solving the Schrödinger equation would be useful? Besides, it is not possible to solve the Schrödinger equation in closed form for general V(x)

There is a mistake in your expression for the current density. There should be a complex conjugation on the second term: j(x,t) \equiv -\frac{i\hbar}{2m} \left(\psi^{*} \partial_{x} \psi - \psi \partial_{x} \psi^{*} \right)
Calculating \partial_{x} j(x,t) is a good place to start - do correct the complex conjugation mistakes though.
Have you tried calculating \partial_{t} \rho?
As for ##\rho##, actually I know my method was wrong. I made ∂Ψ/∂t the subject and then integrated. I don't know how to solve the Schrödinger equation, so I can't find ##\rho##.
 
You don't need to solve the Schrödinger equation to "find" \rho.
\partial_{t} (\psi^{*}\psi) = \psi \partial_{t} \psi^{*} + \psi^{*} \partial_{t} \psi
Now, use the Schrödinger equation to replace \partial_{t} \psi^{*} and \partial_{t} \psi
 
Fightfish said:
You don't need to solve the Schrödinger equation to "find" \rho.
\partial_{t} (\psi^{*}\psi) = \psi \partial_{t} \psi^{*} + \psi^{*} \partial_{t} \psi
Now, use the Schrödinger equation to replace \partial_{t} \psi^{*} and \partial_{t} \psi
Got it, thank you!
 

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