How to determine air-resitance for a dropped coin

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SUMMARY

This discussion focuses on determining air resistance for a coin dropped from a height of 2 meters. It references the Mythbusters episode that measured terminal velocity, which is approximately 40 m/s, while the coin reaches the ground in about 0.67 seconds at a speed of 6.5 m/s. The impact of air resistance is minimal in this scenario due to the short drop distance, and the coin's tumbling motion complicates consistent measurements of drag coefficient.

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  • Understanding of terminal velocity and drag coefficient
  • Familiarity with basic physics concepts related to motion
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  • Awareness of factors affecting air resistance
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16physicist
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Can anyone tell me how I can determine air-resitance for a coin being dropped from 2 meters onto a concrete floor?

Thanks a lot.

-Arash Ay
 
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Depends on what, exactly, you are looking do figure out. Mythbusters did an episode on this, iirc, where they actually measured the terminal velocity, so you could take that and plug it into the terminal velocity equation to find the drag coefficient.

Realistically, though, when dropped from 2 meters, drag will play an insignificant role in what happens. The coin hits the ground in about 2/3 of a second, traveling at 6.5 m/s. The terminal velocity, on the other hand, is probably somwhere around 40 m/s.
 
This would be very difficult because when the coin is dropped it will flip over and over so the same surface will not always be facing the ground. When the flat side is down the resistance will be more than when the thin edge is facing down. But like Russ said it would be so small and would not make much difference.
 
Okay, I apperciate that, thank you.
 

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