How to Determine Charge Distribution in a Coaxial Cable?

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mvpshaq32
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Homework Statement


A long coaxial cable consists of an inner cylindrical conductor with radius a and an outer coaxial cylinder with inner radius b and outer radius c. The outer cylinder is mounted on insulating supports and has no net charge. The inner cylinder has a uniform positive charge per unit length [tex]\lambda[/tex]

Find the charge per unit length on the inner surface and on the outer surface of the outer cylinder.

Homework Equations



[tex]\lambda[/tex]= Q / L

[tex]\phi[/tex]= EA = 2[tex]\pi[/tex]rL = Q / [tex]\epsilon_{0}[/tex]

The Attempt at a Solution



I solved in previous parts that the magnitude of the electric field at any point between the cylinders a distance r from the axis and the magnitude of the electric field at any point outside the outer cylinder a distance r from the axis is both [tex]\lambda[/tex] / 2[tex]\pi[/tex]r[tex]\epsilon_{0}[/tex].

But I have no idea how to find [tex]\lambda_{inner}[/tex] or [tex]\lambda_{outer}[/tex]
 
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hi mvpshaq32! :smile:

(have a phi: φ and a pi: π and an epsilon: ε and a lambda: λ :wink:)
mvpshaq32 said:
I solved in previous parts that the magnitude of the electric field at any point between the cylinders a distance r from the axis and the magnitude of the electric field at any point outside the outer cylinder a distance r from the axis is both [tex]\lambda[/tex] / 2[tex]\pi[/tex]r[tex]\epsilon_{0}[/tex].

But I have no idea how to find [tex]\lambda_{inner}[/tex] or [tex]\lambda_{outer}[/tex]


call the (constant) electric field inside the outer cylider E1, and the charge-per-length on its surfaces ±µ …

then what are the two equations for the change in field as you cross each of the two surfaces? :smile: