How to Determine Charge Distribution in a Coaxial Cable?

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SUMMARY

The discussion focuses on determining the charge distribution in a coaxial cable consisting of an inner cylindrical conductor and an outer coaxial cylinder. The inner cylinder has a uniform positive charge per unit length, denoted as λ. The electric field between the cylinders is expressed as λ / (2πrε₀), and the challenge lies in calculating the charge per unit length on both the inner and outer surfaces of the outer cylinder. Key equations include λ = Q / L and φ = EA = 2πrL = Q / ε₀.

PREREQUISITES
  • Understanding of electrostatics and electric fields
  • Familiarity with coaxial cable structures
  • Knowledge of Gauss's Law
  • Basic algebra and calculus for solving equations
NEXT STEPS
  • Study Gauss's Law applications in cylindrical symmetry
  • Learn about electric field calculations in coaxial cables
  • Explore charge distribution concepts in electrostatics
  • Investigate the effects of insulating materials on charge distribution
USEFUL FOR

Students in physics or electrical engineering, educators teaching electrostatics, and professionals working with coaxial cable designs and applications.

mvpshaq32
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Homework Statement


A long coaxial cable consists of an inner cylindrical conductor with radius a and an outer coaxial cylinder with inner radius b and outer radius c. The outer cylinder is mounted on insulating supports and has no net charge. The inner cylinder has a uniform positive charge per unit length \lambda

Find the charge per unit length on the inner surface and on the outer surface of the outer cylinder.

Homework Equations



\lambda= Q / L

\phi= EA = 2\pirL = Q / \epsilon_{0}

The Attempt at a Solution



I solved in previous parts that the magnitude of the electric field at any point between the cylinders a distance r from the axis and the magnitude of the electric field at any point outside the outer cylinder a distance r from the axis is both \lambda / 2\pir\epsilon_{0}.

But I have no idea how to find \lambda_{inner} or \lambda_{outer}
 
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hi mvpshaq32! :smile:

(have a phi: φ and a pi: π and an epsilon: ε and a lambda: λ :wink:)
mvpshaq32 said:
I solved in previous parts that the magnitude of the electric field at any point between the cylinders a distance r from the axis and the magnitude of the electric field at any point outside the outer cylinder a distance r from the axis is both \lambda / 2\pir\epsilon_{0}.

But I have no idea how to find \lambda_{inner} or \lambda_{outer}


call the (constant) electric field inside the outer cylider E1, and the charge-per-length on its surfaces ±µ …

then what are the two equations for the change in field as you cross each of the two surfaces? :smile:
 

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