How to Determine the Eigenenergy of This Hamiltonian?

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SUMMARY

The discussion focuses on determining the eigenenergy of the Hamiltonian defined as H=Aâ†â + B(â + â†), where â is the annihilation operator and ↠is the creation operator. The hint provided suggests using a new operator b = câ + d, with b† = c↠+ d, to reformulate the Hamiltonian. Participants are encouraged to express H in terms of the new operator b and compare it with the original Hamiltonian to derive the constants c and d in relation to A and B.

PREREQUISITES
  • Understanding of quantum mechanics and operator algebra
  • Familiarity with Hamiltonians and eigenvalues
  • Knowledge of creation and annihilation operators
  • Basic experience with operator transformations in quantum systems
NEXT STEPS
  • Study the derivation of eigenvalues for Hamiltonians in quantum mechanics
  • Learn about operator transformations and their applications in quantum mechanics
  • Explore the role of creation and annihilation operators in quantum field theory
  • Investigate the implications of constants A and B on the eigenenergy of the Hamiltonian
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Quantum physicists, graduate students in physics, and researchers working on quantum mechanics and operator theory will benefit from this discussion.

john go
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The Hamiltonian is given:

H=Aâ†â + B(â + â†)

where â is annihilation operator and ↠is creation operator,
and A and B are constants.

How can I get the eigenenergy of this Hamiltonian?

The given hint is "Use new operator b = câ + d, b† =c↠+ d
(c and d are constants, too)

But I can't use that hint properly.
 
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Form H=b*b. Compare this with the original H, and solve for c and d in terms
of A and B.
 

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