How to Determine the Electric Potential Difference in a Coaxial Cable?

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SUMMARY

The discussion focuses on calculating the electric potential difference in a coaxial cable configuration. The inner conductor has a radius of 0.0025 m and carries a charge of 2.8e-008 C, while the outer conductor, with an inner radius of 0.0075 m and outer radius of 0.008 m, has a charge of -5.6e-006 C. Participants emphasize using Gauss's Law to determine the electric field and subsequently the potential difference between points A and B, suggesting integration of the electric field from the outer conductor to infinity and from the outer conductor to the inner conductor.

PREREQUISITES
  • Understanding of Gauss's Law in electrostatics
  • Familiarity with electric potential and potential difference concepts
  • Knowledge of cylindrical coordinate systems
  • Ability to perform integration in physics contexts
NEXT STEPS
  • Study the application of Gauss's Law in cylindrical geometries
  • Learn how to calculate electric fields for coaxial cables
  • Explore the concept of electric potential and its calculation methods
  • Review integration techniques for electric field calculations
USEFUL FOR

This discussion is beneficial for physics students, electrical engineering students, and anyone involved in studying electrostatics and electric potential in cylindrical systems.

dancer18
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Physics 2 coaxial potential help!

https://wug-s.physics.uiuc.edu/cgi/courses/shell/common/showme.pl?cc/DuPage/phys2112/summer/homework/Ch-22-E-Potential/IE_cylindersV/coax.gif

The diagram above shows a coaxial cable. The inner conductor has radius a = 0.0025 m. The outer conductor is a cylindrical shell with inner radius b = 0.0075 m, and outer radius c = 0.008 m from the center. Both conductors are coaxial. For every length L = 10 m of cable, there is a total charge q = 2.8e-008 C on the inner conductor and a total charge of Q = -5.6e-006 C on the outer conductor.

Determine the electric potential difference between the labeled points A and B.

PLEASE 've been working on this problem for about THREE hours, and I still can't get it! I'm so confused. Please please please!

I tried using the voltage equations from c to b and then adding it w/the voltage from b to a. and it's wrong!
 
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I think you may find first E for r>=c.
Please use Gauss law.
Integral of E from r=c to infinity will give potential at r=c.
Use the condition that potential at infinity = 0.
Go the same way to the center.
 
Last edited:

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