How to Divide a Polynomial by a Binomial Using Long Division

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Homework Help Overview

The discussion revolves around dividing a polynomial, specifically \(x^3 + 4x^2 + 3x\), by a binomial \(3x - 1\) using long division. Participants are exploring the mechanics of polynomial division and the challenges associated with it.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants are questioning how to identify the factor that, when multiplied by \(3x\), equals \(x^3\). There are discussions about using synthetic division and the implications of working with fractions during the division process. Some participants suggest alternative methods to avoid fractions, while others emphasize the importance of following the learned long division method.

Discussion Status

The discussion is ongoing, with various participants offering insights and suggestions. Some participants have expressed confusion and are seeking clarification on specific steps in the division process. There is no explicit consensus, but several productive lines of reasoning are being explored.

Contextual Notes

Some participants mention that the problem is not part of a homework assignment, indicating a desire for understanding rather than completion of an assignment. There are also references to the difficulty of visualizing the division process in a text-based format.

Googl
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Hi all,

Please help understand how this works out. I know how to work it out when 3x-1 has no 3 ie: x-1.

Divide

x^3+4x^2+3x by 3x-1

Thank you
 
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What factor multiplied by 3x equals x^3? That is,

If x^3 = 3x * Z, what must Z equal?
 
Please show us some effort on your part.
 
I'm assuming you're using synthetic division? Show us how you would divide that polynomial by ##\displaystyle x - \frac{1}{3}##.
 
Hi,

What I have posted is actually part of the question. This is not homework. I have worked through the all question, I forgot to mention that I was stuck at that point and gave it a lot of thought but could not think through it.
 
Last edited:
SteamKing said:
What factor multiplied by 3x equals x^3? That is,

If x^3 = 3x * Z, what must Z equal?

Because I have not really came across a problem like this I am finding it even difficult to think about the factor. An example will enlighten me. How about powering it

(3x)^3

and divide by 9.

(3x)^3 / 9

That would not work, would it?
 
If it make it easier, multiply the dividend by 3, then divide, then remember to divide by 3 at the end.

-- I use this trick with matrices a lot.
 
verty said:
If it make it easier, multiply the dividend by 3, then divide, then remember to divide by 3 at the end.

-- I use this trick with matrices a lot.

Hi,

I have tried that but it won't work without leaving decimals/fractions. I will am using long division.
 
Right, then do it the proper way according to the method you have learned, which is what SteamKing pointed out.
 
  • #10
Is there a way of working it out without getting fractions when using long division? I know the factor will be:

(x)^2 / 3
 
  • #11
Why would you NOT want to get fractions?
I suppose you could use "0.333333..." but that would be silly. "3x" divides into x^3 x^2/3 times. That is as easy as you can write it.
 
  • #12
If you have a good understanding how ordinary long division works, this example of yours works the same way, and may be easier.

What I begin to describe here is NOT synthetic division.

You want x^3+4x^2+3x divided by 3x-1.

What is x^3 divided by 3x?
Put this result above the dividend term of x^3. Multiply the entire divisor 3x-1 by your just found result, and write this under the first two terms of the dividend and subtract. Bring down the next term.
Now, what is the leading term you find after the subtraction divided by 3x?

..
You would continue the process. Is the description enough for you to finish this to completion? You may or may not have a remainder.

This is much easier to do on paper than through this text based system for typing.( I KNOW the tags are right. TEX is failing again)
 

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