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And vice-versa? I'm having quite a hard time at doing this. Any tips? My book isn't exactly "layman" friendly. Thanks so much for all the help, I appreciate it.
soothsayer said:Those both look perfect! Yeah, that's exactly the way to do it.
To determine the position from a velocity-time graph, you would need to calculate the area under the curve of the graph. This can be done by dividing the graph into smaller sections (such as rectangles or triangles) and calculating the area of each section. The sum of all the areas will give you the total distance traveled, which is the position at a specific time.
The relationship between velocity-time and position-time graphs is that the slope of a position-time graph represents the velocity at a specific time. In other words, the steeper the slope of the position-time graph, the higher the velocity at that point. Similarly, the area under the curve of a velocity-time graph represents the distance traveled, which is the position at a specific time.
Yes, a position-time graph can have negative values. This indicates that the object has moved in the negative direction, or in the opposite direction of the positive axis. It is important to pay attention to the direction of the position in relation to the time to accurately interpret the motion of an object.
A flat line on a position-time graph indicates that the object is not moving, or its position is not changing over time. This means that the velocity is zero at that point in time. It could also mean that the object is moving at a constant speed, as a straight line with a non-zero slope on a position-time graph represents constant velocity.
To predict the position of an object at a specific time using a velocity-time graph, you can use the slope of the graph to calculate the velocity at that time. Then, you can use the velocity and the initial position to calculate the position at that time using the formula d = v*t + d0, where d is the position, v is the velocity, t is the time, and d0 is the initial position.