Velocity-Time Graph: Dog's Position

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Homework Help Overview

The discussion revolves around analyzing a dog's position as represented in a graph to determine its velocity across three segments. Participants are tasked with sketching a corresponding Velocity-Time Graph based on their calculations.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants share their calculated velocities for different segments and question the accuracy of their x and y values for the Velocity-Time Graph. There are discussions about the interpretation of the graph and the dog's movement, including whether the dog returns to a specific position.

Discussion Status

Several participants have provided feedback on the calculations and interpretations of the graph. There is an ongoing exploration of the values and their implications, with some questioning the assumptions made about the dog's movement and the graph's readings.

Contextual Notes

Participants note the importance of accurately reading values from the graph and discuss the potential discrepancies in interpreting the dog's position at certain points. There is mention of specific time intervals and distances that may influence the calculations.

aatari
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Hi Guys,

I have attempted the question below and would greatly appreciate if I can get some feedback.

A dog's position is recorded in the graph below. Determine the velocity of the dog in all three segments. Sketch the corresponding Velocity-Time Graph. Please See the attached image.

Here are the velocities that I got:

A = 2 m/s
B = 0 m/s
C = -2.42 m/s

Now for the graph that I will make for velocity-time. Do I just use 10, 20, and 28.25 as x-values and then 2, 0, and -2.42 as y-values?
 

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For c, it looks like he moves 15 meters in 6.667 seconds. Edit: -> It looks like it intersects exactly where those two gridlines meet.
 
TomHart said:
For c, it looks like he moves 15 meters in 6.667 seconds. Edit: -> It looks like it intersects exactly where those two gridlines meet.
So you are saying the dog doesn't go all the to 0? So if that's the case is the velocity then 2.27 m/s?
 
aatari said:
Hi Guys,

I have attempted the question below and would greatly appreciate if I can get some feedback.

A dog's position is recorded in the graph below. Determine the velocity of the dog in all three segments. Sketch the corresponding Velocity-Time Graph. Please See the attached image.

Here are the velocities that I got:

A = 2 m/s
B = 0 m/s
C = -2.42 m/s

Now for the graph that I will make for velocity-time. Do I just use 10, 20, and 28.25 as x-values and then 2, 0, and -2.42 as y-values?

upload_2017-2-20_6-12-16.png

aatari said:
Hi Guys,

I have attempted the question below and would greatly appreciate if I can get some feedback.

A dog's position is recorded in the graph below. Determine the velocity of the dog in all three segments. Sketch the corresponding Velocity-Time Graph. Please See the attached image.

Here are the velocities that I got:

A = 2 m/s
B = 0 m/s
C = -2.42 m/s

Now for the graph that I will make for velocity-time. Do I just use 10, 20, and 28.25 as x-values and then 2, 0, and -2.42 as y-values?

The y values are 20 m, 20 m and 0 m, but it is more accurate to read Δx and Δy from the blue triangle.
upload_2017-2-20_6-12-16.png
 
The dog definitely goes to back to y = 0. I am just saying that the point x=26.6666, y = 5 is a lot easier to read than the point at y=0.
 
Ok that is interesting. Thank you guys!
 
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How did you get this number?
C = -2.42 m/s
 

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