How to entangle two particles?

1. Dec 10, 2014

Breo

I have notions of the mathematics involving (entangled state is one which is not a product state of two qubits, etc) the idea of entanglement. However, still can not figure out how to, let us say, pick a particle (which type of particle we can use as qubit? protons? electrons? ununumbiums!?!?) A in one laboratory of Max Planck and a particle B in Boston and then entangle them. How can we entangle 2 arbitrary particles?

2. Dec 10, 2014

VantagePoint72

Entanglement is what generally happens when things interact with each other in a particular way. So if you want to entangle two particles, you must first bring them together so they can interact.

3. Dec 10, 2014

Breo

How? can you bring me an example?

4. Dec 10, 2014

DrChinese

There are a number of methods, and most use some/all of the following concepts:

a) The particles must be indistinguishable on the basis they are entangled. They can be distinguishable on other bases.
b) There is some conserved quantity or relationship between the particles.
c) The number of objects entangled can be 2 or more, with no theoretical upper limit.

1. Photons are most often entangled via a process called Parametric Down Conversion, in which a single photon is split into 2 entangled ones.
2. A helium atom has 2 electrons, which are entangled when in the same lowest shell together.

5. Dec 10, 2014

Jazzdude

I don't see how that is necessary. First of all, you don't even need several particles for entanglement. A single particle with entangled spin and position is very common. Secondly, I don't see what practically speaks against entangling very different quantities between two different particles.

I'm not sure what you mean with this. Can you give an example of how you think this applies?

With the restriction of the monogamy of entanglement: http://www.quantiki.org/wiki/Monogamy_of_entanglement

Allow me to add that two indistinguishable particles are 1) always entangled if they are fermions 2) entangled if they're in different states and bosons.

Cheers,

Jazz

6. Dec 10, 2014

DrChinese

We are both speaking in general terms. However your objections are themselves objectionable. :-)

1. There is no meaningful way to say a single particle is entangled. Entanglement is represented by a system of 2 or more particles.

2. As to conservation: PDC photons are entangled as to frequency with conserved total momentum (from the input photon) according to a common formula. Spin (polarization) is conserved as a constant in type II PDC.

3. Could you give me an example of this? Specifically, what does the "different states" criteria have to do with anything? And just to be clear about MY objection to your concept about entanglement of fermions versus bosons: there is no requirement that entangled particles be the same kind of particle at all.

7. Dec 10, 2014

VantagePoint72

I agree with @Jazzdude. Entanglement is a general property that states in tensor product spaces may have (with respect to that particular factorization); any collection of independent degrees of freedom can be entangled together. That tensor product can be between any two Hilbert spaces, not just those corresponding to separate particles. Entanglement is just more striking when the factor spaces correspond to separate particles because then you can observe the 'spooky' spatial non-locality for which entanglement is famous. But it's perfectly sensible to talk about, say, the spin of a single particle becoming entangled with its angular momentum in spin-orbit coupling. It's exactly the same phenomenon and that is the language widely used.

Given that, again, there's no need for the things being entangled to even be particles, there's no fundamental relationship between entanglement and conservation. Generally, the physical processes that mediate interactions between different degrees of freedom have certain conservation laws associated with them, but that's completely general and nothing to do with entanglement.

Fermions are subject to the Pauli exclusion principle; so, anti-symmetrizing the state of a collection of fermions necessarily produces an entangled state since you cannot start the tensor product of identical pure states. The state of a collection of bosons needs to be symmetric under particle exchange, so each particle is allowed to be in the same pure state giving an overall product state. On the other hand, if you start out with at least two particles in different pure states and then symmetrize the whole thing you get an entangled state as with the fermions.

Last edited: Dec 10, 2014
8. Dec 10, 2014

Jazzdude

This is not accurate. Entanglement happens between tensor factor spaces, not particles. A single nonrelativistic Schroedinger particle of spin 1/2 lives in a space that factors into a Hilbert space spanned by particle positions and a two dimensional spin space. The particle's state does not necessarily factor into states in those two factor spaces however, and the particle can be entangled. A state like $\left| A \right\rangle \left| \uparrow \right\rangle + \left| B \right\rangle \left| \downarrow \right\rangle$ where $A$ and $B$ are different position states is position-spin entangled.

Obviously, conserved quantities must also be conserved for processes that entangle subsystems. I don't see how the existence of a conserved quantity is required for entanglement though. Of course, in the Hamiltonian formalism energy is always conserved under unitary evolution, but that's surely not what you mean.

No, entangled particles do not have to be of the same kind. However indistinguishability is sufficient for entanglement if the states are different. That follows from the (anti)symmetrisation of multi-particle states. Start with a two particle state $\mathcal{H}^{\otimes 2}$ and the two single particle states $\left| A \right\rangle$ and $\left| B \right\rangle$.

The fermionic state is then $\left| A \right\rangle \left| B \right\rangle - \left| B \right\rangle \left| A \right\rangle$ where the order of the kets indicate the space. This state only exists if $\left| A \right\rangle$ and $\left| B \right\rangle$ are different. But in this case the state does not factor and the combined state is entangled.

The bosonic state is $\left| A \right\rangle \left| B \right\rangle + \left| B \right\rangle \left| A \right\rangle$. This state does exist even if $\left| A \right\rangle$ and $\left| B \right\rangle$ are the same single particle state. If they are the same state the state can trivially be written as a product state. If they're not the same the state does not factor and again the combined state is entangled.

Cheers,

Jazz

9. Dec 10, 2014

DrChinese

I agree with this statement. And I also stand by my post #4 as written.

And again you and I disagree on how to address an answer to the OP. What you and Jazzdude are saying is a deeper level than appropriate, in my opinion (and I realize you are a professor). Any answer given can necessarily be argued with on some level. I didn't shred your answer in post #2 as I could have (as I am sure you know perfectly well that entanglement is possible of particles that never even existed at the same time). But that detail wouldn't be of much help to the OP.

My experience here is that some posters benefit from one person's manner of addressing a question, and some from another's. It is common that different approaches are taken to get to that point. It is more effective to assist the OP that to critique someone else's style or approach in the name of "correctness". For the OP's purposes, I believe my answer is better than what you or Jazzdude have said so far. I would encourage you to provide something more for the OP.

To the OP regarding your original question: there are many ways to entangle particles/systems/properties. As you can see from the responses, the fundamental issues can be perceived in a variety of ways. You might enjoy a few of the following references, in which laboratory entanglement creation is discussed.

http://arxiv.org/abs/quant-ph/0205171
http://www.nature.com/nature/journal/v409/n6822/full/409791a0.html
http://arxiv.org/abs/quant-ph/0303018
http://lanl.arxiv.org/abs/1006.4344[/user]

10. Dec 10, 2014

DrChinese

And again my point, we are mixing the general and the specific. This is actually quite nearly what I said earlier: "The particles must be indistinguishable on the basis they are entangled." You objected to that, saying "I don't see how that is necessary." Almost any experiment with entanglement will mention indistinguishably (as I did) and/or show a related equation with something conserved.

I suspect we will both be happier addressing the OP's question, which I believe you have yet to weigh in on.

PS Not that I am questioning that it exists, but I don't recall any actual experiments involving single particle entanglement. Can you cite a good example for me to add to my collection?

11. Dec 10, 2014

Jazzdude

My reply was intended to address certain, unfortunately quite common, misconceptions about entanglement. They were not specifically directed at the OP but are supposed to stand as a footnote to your contribution. I do agree that answers should be tailored to the level of the original question, but they should also be correct. The fact that you objected to my response clearly shows that the misconceptions are not just simplifications. Also, I've contributed to the OPs question by providing an easy way to "produce" entanglement for identical particles. Frankly, and no offence intended, I think your argument for more suitable answers will appear to others as no more than a distraction from your having been wrong. While that's understandable, a good scientist should stand above this.

Cheers,

Jazz

12. Dec 10, 2014

Jazzdude

There is a difference between sufficient and necessary.

Cheers,

Jazz

13. Dec 10, 2014

Jazzdude

Stern-Gerlach will do nicely.

Cheers,

Jazz

14. Dec 10, 2014

DrChinese

As always, I stand ready to acknowledge the limits of my knowledge. Your argument for "correctness", on the other hand, will appear to some others as a distraction* for the lack of utility to the question at hand. Sorry, a good scientist should also be helpful.

-DrC

* I would call it splitting hairs as I see no meaningful disagreement.

15. Dec 10, 2014

DrChinese

You know, I almost wrote that you would answer with that exact phrase. But I thought at the time that you wouldn't waste time with that. Thank you for pointing out precisely nothing useful in an attempt to trump someone.

16. Dec 10, 2014

DrChinese

I am sure the OP will be delighted this helpful nugget found its way into the conversation.

All this from: "How can we entangle 2 arbitrary particles?"

I am loath to add this definition, but we've already gone so far down this road that the devil in me can't resist. :) I will say that I plan to step out of this conversation until the OP returns, at which time I will comment further if I have anything USEFUL to add.

Quantum entanglement is a physical phenomenon that occurs when pairs or groups of particles are generated or interact in ways such that the quantum state of each particle cannot be described independently—instead, a quantum state may be given for the system as a whole.

Last edited: Dec 10, 2014
17. Dec 10, 2014

Jazzdude

Yet you don't but rather reiterate something that is wrong:

If you get something obvious wrong, you will have to live with the obvious being pointed out to you. This has nothing to do with trumping you. I had already pointed out how you're wrong. You however tried to restate it in a more obfuscated way hoping I would let it stand and make it appear that you have been right from the beginning. That is trumping. But even worse, if I answer and undermine your plan you suggest that it's me and not you who is not providing anything useful to the discussion.

Together with this:

I cannot think of any other word but "trolling" for what you are doing.

Now hold it for a minute. You specifically asked me for exactly that information. Giving it to you is now dismissed as not being helpful?

How very convenient for you.

Congratulations!

*plonk*

Jazz

Then, clearly, you have not understood the disagreement.

18. Dec 10, 2014

Breo

Thank you all for your responses.

So, could be the entanglement the more nature way to be for quantum particles?

19. Dec 10, 2014

DrChinese

Atoms and molecules naturally exist in configurations in which there is a lot of entanglement. Which is to say there is a lot of superposition of states. Those are not always useful for entanglement experiments, however. The effort to separate the entangled particles can cause them to cease acting as a combined system and instead act as separate ones.

20. Dec 10, 2014

Breo

That should be taught on my quantum mechanics course...

When we use Bell's basis? Which is his usefulness? We use different basis each case of entanglement?

I ask these questions in order to perform a more important one.