How to Establish the Inequality xcosx < sinx < x Using the Unit Circle?

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SUMMARY

The inequality xcosx < sinx < x for 0 < x < π/2 can be established using the unit circle. This proof is a well-known mathematical challenge often encountered in calculus and trigonometry courses. The provided resource, a PDF from California State University Northridge, outlines the first part of the proof, which is essential for understanding the relationships between the sine and cosine functions in this context. The discussion confirms that this inequality is a classic problem that many can solve.

PREREQUISITES
  • Understanding of trigonometric functions, specifically sine and cosine.
  • Familiarity with the unit circle and its properties.
  • Basic knowledge of inequalities in calculus.
  • Experience with mathematical proofs and problem-solving techniques.
NEXT STEPS
  • Review the PDF resource on sine inequalities from California State University Northridge.
  • Study the properties of the unit circle in relation to trigonometric functions.
  • Practice establishing other trigonometric inequalities using graphical methods.
  • Explore advanced calculus concepts related to limits and continuity in trigonometric functions.
USEFUL FOR

Mathematics students, educators, and anyone interested in deepening their understanding of trigonometric inequalities and proofs.

theperthvan
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This was an exam question I had at the end of 2005 in my uni entrance exams.
Can you do it?

Establish the inequality

[tex]xcosx < sinx < x[/tex] where [tex]0<x<pi/2[/tex] using the unit circle.

is the tex working?
 
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This is a classic. Here:

http://www.csun.edu/~ac53971/courses/math350/xtra_sine.pdf"

The first part of the proof is what you are looking for.

Edit: Is it a challenge? If so then most people here will be able to do it, this is a very known proof.
 
Last edited by a moderator:
That was quick!

Yes, that's it. Cheers,
 

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