How to evaluate this probability

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Discussion Overview

The discussion revolves around evaluating the probability P defined by the inequality involving three independent exponentially distributed random variables x, y, and z, with specified means. Participants explore the implications of varying a constant k on the probability, particularly noting issues when k is greater than zero.

Discussion Character

  • Exploratory
  • Technical explanation
  • Mathematical reasoning
  • Debate/contested

Main Points Raised

  • One participant presents the probability P as P={ z + x*y/(y+a) > x/(x*k+1)} and notes that for k=0, P lies between 0 and 1, but for positive k, P exceeds 1, which is problematic.
  • Another participant questions the clarity of the notation and seeks confirmation on the definition of the event related to the probability.
  • Participants discuss the challenges in obtaining a closed form for the probability and mention using MATLAB to plot the probability for different values of xbar.
  • There is a suggestion that the problem may involve triple integration due to the three independent random variables, and one participant mentions successfully evaluating one integration but struggling with the others.
  • Concerns are raised about the validity of plotting the probability without a clear formula, with suggestions for using Monte-Carlo simulations as an alternative approach.

Areas of Agreement / Disagreement

Participants express uncertainty regarding the evaluation of the probability and the implications of the variable k. There is no consensus on how to resolve the issue of the probability exceeding 1 or on the correct method for evaluating P.

Contextual Notes

Participants mention potential mistakes in their evaluations and the limitations of their current approaches, including the need for further integration and the challenges of defining the functions involved.

GW008
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P={ z + x*y/(y+a) > x/(x*k+1)}
where x,y,z are exponentially distributed with mean xbar,ybar,zbar.
a,k are constants.
please suggest me how to evaluate this probability...
for k=0, P lies between 0 and 1 but for any positive value of k, P become higher than one which is unacceptable...
take xbar=1 ybar=3.14 zbar=1
 
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GW008 said:
P={ z + x*y/(y+a) > x/(x*k+1)}
where x,y,z are exponentially distributed with mean xbar,ybar,zbar.
a,k are constants.

Your notation is unclear. Are you asking for the probability P of an event defined by the set:
{(x,y,z) such that z + x*y/(y+a) > x/(x*k + 1) } ?

for any positive value of k, P become higher than one which is unacceptable...
take xbar=1 ybar=3.14 zbar=1

How did you arrive at that conclusion?
 
Stephen Tashi said:
Your notation is unclear. Are you asking for the probability P of an event defined by the set:
{(x,y,z) such that z + x*y/(y+a) > x/(x*k + 1) } ?

sorry for applying equal to sign, Yes u asking me right question

How did you arrive at that conclusion?

I try to solve this probability but I didn't get its close form so I plot it in MATLAB for different values of xbar.
But as I take the value of k greater than zero, Probability became larger than one...

Please suggest something
 
GW008 said:
so I plot it in MATLAB for different values of xbar.

"It"? Plot what? You aren't stating the problem clearly. What function did you plot?
 
Stephen Tashi said:
"It"? Plot what? You aren't stating the problem clearly. What function did you plot?

"It refers to probability here.

probability of positive secrecy = P{ z + x*y/(y+a) > x/(x*k+1)}
where x,y,z are exponentially distributed with mean xbar,ybar,zbar.
a,k are constants.
please suggest me how to evaluate this probability...
for k=0, P lies between 0 and 1 but for any positive value of k, P become higher than one which is unacceptable...
ybar=3.14 zbar=1

I tried to solve this Probability to some extent but unable to express Probability in closed form. So, I plot this probability for different values of xbar(0-100). for k=0, this probability decrease from 1 to 0 but for k>0 this probability increase from 1 to 2.5 which is unacceptable...

I think now you might get what I am want to tell...
 
GW008 said:
"It refers to probability here.

If you are going to plot a function, "it" must be a function. What function are you plotting? What is its formula?

The general form of your question appears to be:

X,Y,Z are independent random variables
f(x,y,z), g(x,y,z) are given functions.
S is the event {(x,y,z) such that f(X,Y,Z) > g(X,Y,Z) }
Find P(S)

But what are you plotting? It wouldn't make sense to plot f(X,Y,Z) or g(X,Y,Z).

If you don't know the formula for P(S), how can you plot anything? You could run a Monte-Carlo simulation and estimate P(S), but that would never produce a number greater than 1.
 
Thanks for the above advise...

As event S has three random variables (all are independent) that means P(S) is a case of triple integration. I solve one integration but unable to evaluate other two integrations. In matlab, we can directly plot integral equation using function "integral , integral2, integral3". I use "integral2' to evaluate P(S) and plot it by varying xbar for different values of k...for k=0, this probability decrease from 1 to 0 but for k>0 this probability increase from 1 to 2.5.

It can be happened that i evaluate that first integration wrong or i did some other mistake... Please evaluate P(s)...
Thanks
 

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