How to exponentiate a 3*3 matrix with all diagonal entries equal to zero?

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To exponentiate a 3x3 matrix with all diagonal entries equal to zero, diagonalization is a key technique, but if the matrix is not diagonalizable, the Jordan canonical form must be used. The specific matrix discussed is related to the angular momentum operator Ly, represented as a 3x3 matrix. Eigenvalues of the matrix are found to be 1, -1, and 0, leading to the construction of a basis of eigenvectors. The matrix can be expressed in the form A = PDP^-1, where D is diagonal, allowing for the calculation of the matrix exponential using the relation e^A = e^(PDP^-1). Understanding these steps is crucial for successfully exponentiating such matrices.
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QM--- matrix exponentiation

Homework Statement



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How do you go about exponentiating a 3*3 matrix? for example if you have

<θ,∅|exp(-i*∅*Ly/h)|l,m>



Homework Equations



I know how to exponentiate a two cross two diagonalized matrix. you just exponentiate the diagonal terms. However, in my question, all diagonal entries are zero. So what do I do?
 
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Can you give the actual matrix??

I think the best technique is trying to diagonalize the matrix. Then use the result of diagonal matrices.

If the matrix is not diagonalizabe, then you'll need to compute the Jordan canonical form.
 
k* 0 1 0
1 0 1
0 1 0

That's the matrix of Ly for l=1.
 
So, what if you try to diagonalize it?
 
I will get the eigenvalues 1, -1, 0
 
Can you find a basis of eigenvectors?
 
Yes I found the the eigen basis.
 
OK, so you expressed

##A = PDP^{-1}##

with ##D## diagonal.

Now, you need to calculate

e^{A} = e^{PDP^{-1}}

Now use the definition of the matrix exponential and use that ##(PDP^{-1})^k = PD^k P^{-1}##.
 

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