How to exponentiate a 3*3 matrix with all diagonal entries equal to zero?

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    Matrix Qm
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Homework Help Overview

The discussion revolves around the process of exponentiating a 3x3 matrix, specifically one with all diagonal entries equal to zero. The original poster expresses familiarity with exponentiating diagonalized matrices but seeks guidance on how to approach this situation.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss techniques such as diagonalization and the Jordan canonical form as potential methods for handling the matrix exponentiation. There are inquiries about the specific matrix and its eigenvalues, as well as the existence of a basis of eigenvectors.

Discussion Status

The conversation is actively exploring various methods for exponentiating the matrix. Some participants have provided insights into diagonalization and the calculation of eigenvalues, while others are considering the implications of the matrix's structure. There is no explicit consensus yet, but productive lines of inquiry are being pursued.

Contextual Notes

Participants note the challenge posed by the matrix having all zero diagonal entries, which raises questions about the applicability of standard methods for matrix exponentiation.

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QM--- matrix exponentiation

Homework Statement



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How do you go about exponentiating a 3*3 matrix? for example if you have

<θ,∅|exp(-i*∅*Ly/h)|l,m>



Homework Equations



I know how to exponentiate a two cross two diagonalized matrix. you just exponentiate the diagonal terms. However, in my question, all diagonal entries are zero. So what do I do?
 
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Can you give the actual matrix??

I think the best technique is trying to diagonalize the matrix. Then use the result of diagonal matrices.

If the matrix is not diagonalizabe, then you'll need to compute the Jordan canonical form.
 
k* 0 1 0
1 0 1
0 1 0

That's the matrix of Ly for l=1.
 
So, what if you try to diagonalize it?
 
I will get the eigenvalues 1, -1, 0
 
Can you find a basis of eigenvectors?
 
Yes I found the the eigen basis.
 
OK, so you expressed

##A = PDP^{-1}##

with ##D## diagonal.

Now, you need to calculate

e^{A} = e^{PDP^{-1}}

Now use the definition of the matrix exponential and use that ##(PDP^{-1})^k = PD^k P^{-1}##.
 

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