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How to find abundance of 206, 207 and 208 Pb

  1. Nov 21, 2008 #1
    how would i find the abundance of Pb 206, 207 and 208 if im given the isotopic data of 207Pb/206Pb and 208Pb/206Pb?
     
  2. jcsd
  3. Nov 21, 2008 #2

    chemisttree

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    Pending...
     
  4. Nov 24, 2008 #3

    chemisttree

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    OK... Assume that the expression 206Pb means the molar fraction of lead-206. The same is true for 207Pb and 208Pb. You know that the molar fractions sum to 1 as well as the molar ratios of 207Pb/206Pb and 208Pb/206Pb. You can also calculate 207Pb/208Pb. From here it is merely solving for the simultaneous equations.
     
  5. Nov 24, 2008 #4
    ok, i think i get it. heres my scenerio,
    the Pb content is 468ppm
    207Pb/206Pb= 0.2515
    208Pb/206Pb= 0.0581
    i could just use abgebra to find each right?
    206=x
    207=0.2515x
    208=0.0581x
    i just solve for x and put it back into the previous equation?
     
  6. Nov 25, 2008 #5

    chemisttree

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    I would use the definition... 206Pb + 207Pb + 208Pb = 1
     
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