How to find an unknown in a cubic equation iF you are given a factor?

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Homework Help Overview

The discussion revolves around finding an unknown coefficient in a cubic equation, specifically x^3 + x^2 + ax - 72, given that x + 3 is a factor of the polynomial. Participants are exploring the implications of this factorization and the conditions under which it holds true.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants are questioning why substituting -3 into the polynomial does not yield zero, which is a requirement for x + 3 to be a factor. There are suggestions to perform synthetic division or polynomial division to find the unknown coefficient a.

Discussion Status

The discussion is ongoing, with participants providing guidance on the relationship between roots and coefficients, and exploring different methods to approach the problem. There is no explicit consensus yet, as some participants are still seeking clarification on the original poster's calculations.

Contextual Notes

There is an indication that the original poster may not have fully grasped the implications of the factor theorem, as they assert that F(-3) does not equal zero, which contradicts the premise of x + 3 being a factor.

Beurre
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An example is x^3 + x^2 + ax -72
Factor is x+3
F(-3) doesn't equal zero and I am out of other ideas. Help? :/
 
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If x+3 is a factor then F(-3) = 0. Why do you think F(-3) is not 0? What would make it 0?
 
Beurre said:
An example is x^3 + x^2 + ax -72
Factor is x+3
F(-3) doesn't equal zero and I am out of other ideas. Help? :/

thats the problem, think without any exemple.
 
Beurre said:
An example is x^3 + x^2 + ax -72
Factor is x+3
F(-3) doesn't equal zero and I am out of other ideas. Help? :/
Hello Beurre. Welcome to PF !

What is F(-3) ?
 
Have you learned the relationship between roots and coefficients?
[tex]S_n = x_1x_2...x_n = (-1)^n \dfrac{a_0}{a_n}[/tex]
That is, the sum of the roots taken n at a time (in all possible combinations) equals the constant term divided by the nth coefficient multiplied by negative one raised to the nth power. I encourage you to research why this is true, so you don't blindly use the theorem. Regardless, let
[tex]P(x) \textrm{ have roots } x_1, x_2, \textrm{ and } x_3[/tex]
Then [tex]S_1 = x_1 + x_2 + x_3 ; S_2 = x_1x_2 + x_1x_3 + x_2x_3 ; S_3 = x_1x_2x_3[/tex] If not, and you are given at least one root and there is one coefficient missing, you can do synthetic division with x = -3 and deduce what that value must be.
I can't really type synthetic division out here, but try doing it, because you know that the some value times a must equal 72.
 
Last edited:
Beurre don't seem to have got back to us.

Beurre, have you been able to do this? If not, since you assert that "F(-3) doesn't equal zero", what do you think it does equal?
 
Beurre said:
An example is x^3 + x^2 + ax -72
Factor is x+3
You could do long hand polynomial division of the cubic equation by the known factor in order to end up with a quadratic equation and a remainder that will be some linear function of a, which you can then solve for a, or as already suggested subsitute x = -3 into the equation and solve for a.
 

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