How to find out combination from following situation

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Discussion Overview

The discussion revolves around determining the number of combinations for three numbers, each of which can have two statuses ("a" or "b"), with specific conditions on their statuses. The problem is framed within the context of introductory statistics and combinatorial reasoning.

Discussion Character

  • Exploratory
  • Mathematical reasoning
  • Homework-related

Main Points Raised

  • One participant presents a scenario involving three numbers (1, 2, 3) that can each have two statuses, "a" or "b", and seeks to find the total number of combinations.
  • Another participant suggests applying the fundamental counting principle to determine the number of combinations based on the possible states of each number.
  • It is clarified that number 1 can only have the status "a", which alters the calculation of combinations.
  • Participants discuss the need to multiply the number of states for each number to find the total combinations.
  • Links to resources for formulating large numbers are requested by a participant.

Areas of Agreement / Disagreement

Participants generally agree on the approach of using the fundamental counting principle, but there is no consensus on the exact number of combinations due to the specific condition placed on number 1.

Contextual Notes

The discussion does not resolve the exact number of combinations due to the differing statuses of the numbers and the specific condition on number 1. There are also references to external resources for further exploration of the topic.

Who May Find This Useful

Individuals interested in combinatorial problems, introductory statistics, or those seeking to understand counting principles may find this discussion relevant.

rajemessage
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Dear All,

There are three numbers they can have two status "a" or "b".
only one status can exist at one time for a number.
I have to chose three number(1,2,3) , they will be in this order only.
, so please tel how many combination
can be there?

1(a)
2(a)
2(b)
3(a)
3(b)

yours sincerley
 
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Hello and welcome to MHB! :D

I have moved this thread because while it may be given in a university course, it is the type of problem you would find in an introductory course in statistics.

Now, you want to apply the fundamental counting principle. The number of combinations here will be the product of each numbers possible states...what would that be?
 
MarkFL said:
Hello and welcome to MHB! :D

I have moved this thread because while it may be given in a university course, it is the type of problem you would find in an introductory course in statistics.

Now, you want to apply the fundamental counting principle. The number of combinations here will be the product of each numbers possible states...what would that be?

sorry, i forgot to mention 1 will have only one status "a"

if possible please send me some links , with which i can formulate big numbers.yours sinclerely
 
rajemessage said:
sorry, i forgot to mention 1 will have only one status "a"

if possible please send me some links , with which i can formulate big numbers.yours sinclerely

That's okay, the problem is still worked in the same way, you will just have a different factor representing the number of states for "1." You want the number of states for "1" times the number of states for "2" times the number of states for "3"...what will this product be?

As for a site that will let you formulate numbers large and small, I recommend:

Wolfram|Alpha: Computational Knowledge Engine
 
MarkFL said:
That's okay, the problem is still worked in the same way, you will just have a different factor representing the number of states for "1." You want the number of states for "1" times the number of states for "2" times the number of states for "3"...what will this product be?

As for a site that will let you formulate numbers large and small, I recommend:

Wolfram|Alpha: Computational Knowledge Engine

yes
 

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