- #1
iVenky
- 212
- 12
Let
y=F(z) where z=x-vt
Now I can find out the value of
[itex] \frac{\partial y}{\partial t} [/itex]
but I don't know how to find out the
[itex] \frac{\partial ^{2} y}{\partial t^{2}} [/itex]
I know that this is equal to
[itex] \frac{d^{2}F}{dz^{2}} (-v)^2 [/itex]I tried to solve this in this way- just tell me if this is correct
[itex] \frac{ \partial y}{ \partial t}= \frac{dF}{ dz} \frac{ \partial z}{ \partial t}=\frac{dF}{dz} (-v)
\\
\frac{ \partial^{2} y}{ \partial t^{2}}= \frac{\partial }{\partial t} \frac{dF}{dz} (-v)= \frac{d}{dz}\frac{\partial z}{\partial t} \frac{dF}{dz} (-v) = \frac{d^{2}F}{dz^{2}} (-v)^2
[/itex]
Just tell me if the above method is correct
Thanks a lot
y=F(z) where z=x-vt
Now I can find out the value of
[itex] \frac{\partial y}{\partial t} [/itex]
but I don't know how to find out the
[itex] \frac{\partial ^{2} y}{\partial t^{2}} [/itex]
I know that this is equal to
[itex] \frac{d^{2}F}{dz^{2}} (-v)^2 [/itex]I tried to solve this in this way- just tell me if this is correct
[itex] \frac{ \partial y}{ \partial t}= \frac{dF}{ dz} \frac{ \partial z}{ \partial t}=\frac{dF}{dz} (-v)
\\
\frac{ \partial^{2} y}{ \partial t^{2}}= \frac{\partial }{\partial t} \frac{dF}{dz} (-v)= \frac{d}{dz}\frac{\partial z}{\partial t} \frac{dF}{dz} (-v) = \frac{d^{2}F}{dz^{2}} (-v)^2
[/itex]
Just tell me if the above method is correct
Thanks a lot
Last edited: