How to find solutions to a Legendre equation?

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SUMMARY

The discussion focuses on solving the Legendre equation given by (1-x^2)y^{n-2}y' + λy = 0 with boundary conditions y(0)=0 and bounded y(x) and y'(x) on the interval [-1, 1]. The user identifies that n is odd and seeks guidance on determining the first three positive values of λ for nontrivial solutions. The conversation highlights the necessity of finding a series solution, emphasizing that λ must adhere to specific constraints to ensure boundedness of the solutions.

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Homework Statement



Find the first three positive values of \lambda for which the problem:

(1-x^2)y^n-2xy'+\lambda y = 0, \ y(0)=0, \ y(x) & y'(x) bounded on [-1, 1]

has nontrivial solutions.

Homework Equations



When n is even:

y_1(x) = 1 - \frac{n(n+1)}{2!}x^2 + \frac{(n-2)(n(n+1)(n+3)}{4!} - ...

When n is odd:

y_2(x) = x - \frac{(n-1)(n+2)}{3!} + \frac{(n-3)(n-1)(n+2)(n+4)}{5!} - ...

The Attempt at a Solution



I was able to do part of the problem myself. By plugging in zero into both of the above equations and then comparing to initial conditions, I was able to determine that n is odd. However, I don't know what to do next.

My textbook does not have *any* examples for this type of problem and I haven't been able to find anything I understand online. I looked the problem up on Chegg and found it here:

http://www.chegg.com/homework-help/a-first-course-in-differential-equations-with-modeling-applications-10th-edition-chapter-6.4-problem-47e-solution-9781111827052

Steps 1-2 on there are basically what I did, but then they jump to the answer in step 3 with zero explanation as to how they got there.

I don't want to just copy what they did with no understanding of how they got there, I want to actually understand it.. Can anyone explain what I need to do next to get the solutions?

Thanks :)
 
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The usual approach is to find a series solution. The requirement that y and y' remain bounded requires that ##\lambda## take on only certain values.
 

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