How to Find Speed and Tension in a Swinging Rock?

Click For Summary
SUMMARY

The discussion focuses on calculating the speed of a rock and the maximum tension in a string during its motion. The rock, with a mass of 3.3 kg, is attached to a 1.2 m string and released from a 25-degree angle. The maximum tension in the string is calculated using the formula T=ma, resulting in a tension of 32.34 N. To find the speed of the rock at the lowest point of its trajectory, further analysis of the forces and energy conservation principles is required.

PREREQUISITES
  • Understanding of Newton's Second Law (T=ma)
  • Basic principles of pendulum motion
  • Knowledge of gravitational force calculations
  • Familiarity with energy conservation in physics
NEXT STEPS
  • Calculate the speed of the rock using energy conservation principles
  • Explore the dynamics of pendulum motion and its equations
  • Investigate the effects of angle on tension in pendulum systems
  • Review examples of similar physics problems involving tension and speed
USEFUL FOR

Students studying physics, particularly those focusing on mechanics and pendulum motion, as well as educators looking for examples of tension and speed calculations in real-world applications.

Noke2011
Messages
2
Reaction score
0
Maximum Tension and Trajectories?

Homework Statement



A rock of mass 3.3kg is tied to a string of length 1.2m. The rock is held at rest (at an angle of 25 degrees) so that the string is initially tight, and then it is released. (A) Find the speed of the rock when it reaches the lowest point of its trajectory. (B) What is the maximum tension in the string?


Homework Equations



T=ma


The Attempt at a Solution



Okay, so the max tension is the amount of tension that can be applied so that the string is taught, therefore T=(3.3)(9.8)=32.34N. However, my question is, if it's held taught, and the string length cannot change, wouldn't the lowest point of the trajectory be the point at which the string is held?
 
Physics news on Phys.org


The string length will stay the same and the string will still be taught, but the angle(and therefore the x and y coordinates of the rock) will change after released.
 


But how do I find the speed of the rock at this angle? I'm not sure where to begin, would the angle just be the opposite of 25 degrees?
 

Similar threads

  • · Replies 1 ·
Replies
1
Views
3K
Replies
8
Views
2K
Replies
7
Views
4K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 19 ·
Replies
19
Views
2K
  • · Replies 19 ·
Replies
19
Views
5K
Replies
19
Views
5K
  • · Replies 1 ·
Replies
1
Views
4K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 3 ·
Replies
3
Views
1K