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How irregular is this? The picture makes it look like a right trapezoid, which has a known formula.Srinivas said:https://www.physicsforums.com/attachments/11884
Two right angles.topsquark said:How irregular is this? The picture makes it look like a right trapezoid, which has a known formula.
There may be a way to get the area of a quadrilateral using only the sides (like Heron's formula for triangles) but the only process I'm sure of requires knowledge of one of the angles as well. The usual method for finding the area of an irregular figure is to break it into triangles and find the sum of the areas of the triangles. If you have the angle of just one of these triangles you can find the length of the diagonal and can use Heron's formula to find the area of the triangle. Then you can get the other two angles and work from there.
-Dan
Okay, so this is not an irregular quadrilateral, it's a right trapezoid. The area for a trapezoid is $A = \dfrac{1}{2} (b_1 + b_2) h$. What can you use for the bases and the height?Srinivas said:Dan, two right angles are there in the image.
It wasn't clear from the drawing that the angles at the base were right angles.Srinivas said:Dan, two right angles are there in the image.
If I'm not mistaken, the quadrilateral in the picture cannot exist. Could you double check the numerical values of the problem, please? Just to make sure, we're talking about the right problem.Srinivas said:Dan, two right angles are there in the image.