Undergrad How to find the integrating factor? (1st order ODE)

Click For Summary
The discussion focuses on finding the integrating factor for the first-order ordinary differential equation (ODE) given by x² + y + y²dx - x dy = 0. The proposed integrating factor is I(x,y) = -1 / (x² + y²). Participants question the validity of using certain methods to solve the ODE, specifically the equations involving g(x) and h(y), suggesting that mixing infinitesimals and non-infinitesimals leads to confusion. Clarification is sought regarding the correct formulation of the ODE, emphasizing the need for proper notation. The conversation highlights the importance of correctly identifying integrating factors in solving first-order ODEs.
hellotheworld
Messages
4
Reaction score
0
x2 + y + y2dx - x dy = 0

Integrating factor, I(x,y) = -1 / (x2 + y2)

How to find the integrating factor ?Why I cannot use below method to solve the ode ?

(1/N)(My - Nx) = g(x) , I(x,y)=exp( ∫ g(x) dx) OR
(1/M)(My - Nx) = h(y) , I(x,y)=exp( -∫ h(y) dy)
 
Physics news on Phys.org
hellotheworld said:
x2 + y + y2dx - x dy = 0
That equation makes no sense. You cannot mix infinitesimals and non-infinitesimals like that.
 
hellotheworld said:
x2 + y + y2dx - x dy = 0
Did you mean ##(x^2 + y + y^2)dx - x dy = 0##?
hellotheworld said:
Integrating factor, I(x,y) = -1 / (x2 + y2)

How to find the integrating factor ?Why I cannot use below method to solve the ode ?

(1/N)(My - Nx) = g(x) , I(x,y)=exp( ∫ g(x) dx) OR
(1/M)(My - Nx) = h(y) , I(x,y)=exp( -∫ h(y) dy)
 

Similar threads

  • · Replies 3 ·
Replies
3
Views
4K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 2 ·
Replies
2
Views
4K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 9 ·
Replies
9
Views
3K