The discussion centers on finding the intersection point between two lines represented in vector form. The lines are defined as line 1: r = (3,1,-1) + s(1,2,3) and line 2: r = (2,5,0) + t(1,-1,1). Participants clarify that the parameters s and t must be distinct for each line equation, emphasizing the need for different parameters to solve for the intersection. The general form of a line equation is confirmed as r = a + s * d, where a is a point on the line and d is the direction vector.
PREREQUISITESMathematicians, physics students, engineers, and anyone interested in understanding vector geometry and line intersections.
Raerin said:
Haha! It Was a typo I see! I Was trying and trying, i Was like how can $$3+s= 2+s$$I like Serena said:Hey Raerin! ;)
Let's use a different parameter in both of those line equations.
line 1: r = (3,1,-1) + s(1,2,3)
line 2: r = (2,5,0) + t(1,-1,1)
We're looking for an $s$ and a $t$, such that the resulting r is the same...Btw, perhaps you could also put your question inside your post instead of only as the title of the thread.
Your post looks a bit out of context now.
I like Serena said:Hey Raerin! ;)
Let's use a different parameter in both of those line equations.
line 1: r = (3,1,-1) + s(1,2,3)
line 2: r = (2,5,0) + t(1,-1,1)
We're looking for an $s$ and a $t$, such that the resulting r is the same...Btw, perhaps you could also put your question inside your post instead of only as the title of the thread.
Your post looks a bit out of context now.
Raerin said: