How to find the maximum velocity and maximum acceleration?

  • Thread starter dumpman
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  • #1
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Homework Statement


The position of a particle moving along an x axis is given by x=12t^2-2t^3, what is the maximum positive coordinate, velocity and acceleration reached by the particle?

Homework Equations





The Attempt at a Solution


I took derivative of the quadratic and got V=24t-6t^2 and set it =0, then i solve for t and substituted in x=12t^2-2t^3 to get the max. positive coordinate.
But I dont know what to do to solve for the max velocity and acceleration:confused:
 

Answers and Replies

  • #2
1,860
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You have the velocity as a function of time, just like you had the position as a function of time.
 
  • #3
17
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more hints?
 
  • #4
1,860
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Why not repeat the same process for your function of velocity?
 
  • #5
17
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Oh, so i set a=0 to find max velocity, but then what do I do to find the max acceleration?
 
  • #6
1,860
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Find the derivative of acceleration as a function of time and set it to zero. The physical term for the fourth derivative time is called jerk.
 

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