How to find the pH of HCl and NaOH combined.

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SUMMARY

The discussion focuses on calculating the pH of a solution resulting from the titration of 0.100M HCl with 0.100M NaOH. The initial volume of HCl is 100mL, leading to 0.01 moles of HCl. The pH is calculated using the formula pH = -log[H3O+], resulting in a pH of 2 when no NaOH is added. The conversation highlights the importance of understanding hydronium ion concentration and the water ion product, clarifying that pH is not simply the negative logarithm of acid concentration in all scenarios.

PREREQUISITES
  • Understanding of acid-base titration concepts
  • Knowledge of pH calculations and the pH scale
  • Familiarity with hydronium ion concentration
  • Basic grasp of the water ion product (Kw)
NEXT STEPS
  • Study the relationship between pH and hydronium ion concentration
  • Learn about the water ion product (Kw) and its application in various solutions
  • Explore the concept of neutralization in acid-base reactions
  • Investigate the effects of dilution on pH and concentration
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Chemistry students, educators, and anyone involved in laboratory work related to acid-base titrations and pH calculations.

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Homework Statement


I have .100mL of .100M HCl titrated with .100M NaOH, there's a chart I have to fill in and I'm completely lost. I have the volume of NaOH(from 0ml-200ml) I have to find the total volume of the solution, I get that, moles remaining of solution molarity of remaining solution the hydronium ion concentration the OH concentration and the pH


Homework Equations





The Attempt at a Solution


0.00mL of NaOH added, so the volume is .01L, the moles remaining would also be .01 because 100mL*.100M HCl, the pH is just -log.01 then, resulting in 2. I don't know how to get the Hydronium ion concentration or concentration of OH, any help is welcome.
 
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I read the water ion product, that would apply to solutions not diluted?
 
It applies to all solutions.

But you should start learning about hydronium and pH. In general pH is NOT minus log of the acid concentration (even if in some specific circumstances it can be calculated this way).
 
I talked to my teacher and he just wanted us to find the pH as the -log way. But I got it, thank you for the help
 
I don't see how you were able to solve the problem using incorrect pH definition. Can you elaborate?
 

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