MHB How to Find the Point of Intersection Between ln x and 5-x?

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The discussion focuses on finding the point of intersection between the functions ln x and 5-x, which is calculated to be approximately x=3.69344. It suggests using integrals to determine the area between the curves, with two approaches presented: one involving the integral of ln x from 1 to a and the other using the integral of (5-y) - e^y. Additionally, a volume calculation is proposed using similar cross-section integrals. The conversation hints at further exploration of the problem, particularly in part (c). Overall, the thread emphasizes the mathematical methods for analyzing the intersection and area between the two functions.
karush
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Ok this might take a while...
but first find point of intersection $\ln x=5-x$
which calculates to $x=3.69344$ which maybe there is more simpler approach
 
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this is a calculator active problem ...

$\displaystyle R = \int_1^a \ln{x} \, dx + \int_a^5 5-x \, dx$
where $a$ is the x-value of the intersection.

or ...
$\displaystyle R = \int_0^b (5-y) - e^y \, dy$
where $b$ is the y-value of the intersection.

can you set up the volume by similar cross-section integral ?
 
$\displaystyle V = \int_1^a (\ln{x})^2\, dx + \int_a^5 (5-x)^2 \, dx$
 
ok ... continue with part (c)
 
skeeter said:
ok ... continue with part (c)
if we chanhge b to k
$\displaystyle \int_0^k (5-y) - e^y \, dy = \dfrac{1}{2} A$
then solve for k y was derived previous
anyway...