- #1

karush

Gold Member

MHB

- 3,269

- 5

find y'

$\quad y= x\ln{x}-x$

so

$\quad y'=(x\ln{x})'-(x)'$

product rule

$\quad (x\ln{x})'=x\cdot\dfrac{1}{x}+\ln{x}\cdot(1)=1+\ln{x}$

and

$\quad (-x)'=-1$

finally

$\quad \ln{x}+1-1=\ln{x}$

well this is an even # with no book answer but I think it is ok

typos maybe

also guess we could of factored out the x but not sure if this would help