MHB How to Generate a Function for Vertex Distance in a Planar Tree?

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To generate a function for vertex distance in a planar tree, the focus is on finding an exponential generating function for the distances from the root. The discussion emphasizes using the Lagrange Inversion Theorem to derive the necessary results. A specific formula for the total number of vertices at distance $d$ from the root is presented, which is $$\displaystyle \binom{2n}{n-d}\frac{2d+1}{(n+d+1)}$$. Participants are encouraged to share any progress or partial proofs related to the problem. The conversation highlights collaborative problem-solving in combinatorial mathematics.
Howang
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Hi,

Please I need you help to solve this problem:

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Consider a planar tree with $n$ non-root vertices (root edge selected).

1. Give a generating function for vertices distance $d$ from the root.
2. Proof that the total number is $$\displaystyle \binom{2n}{n-d}\frac{2d+1}{(n+d+1)}$$

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We are supposed to have an exponential generating function then use Lagrange Inversion Theorem.
 
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Hello there, Howang! :D

Have you managed a partial proof, or made any inroads into solving this problem? If so, please DO share.

Thanks!

Gethin
 
First trick I learned this one a long time ago and have used it to entertain and amuse young kids. Ask your friend to write down a three-digit number without showing it to you. Then ask him or her to rearrange the digits to form a new three-digit number. After that, write whichever is the larger number above the other number, and then subtract the smaller from the larger, making sure that you don't see any of the numbers. Then ask the young "victim" to tell you any two of the digits of the...

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