How to go from acceleration vs time graph to velocity vs time graph?

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Homework Help Overview

The discussion revolves around converting an acceleration versus time graph into a velocity versus time graph for a motorcyclist. The original poster provides initial conditions and outlines several related questions, focusing on graphical analysis rather than kinematic equations.

Discussion Character

  • Exploratory, Conceptual clarification, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the relationship between acceleration and velocity, particularly how the slope of the velocity graph relates to the acceleration graph. Questions arise about how to determine the slope of the velocity graph when it is the target of the analysis.

Discussion Status

Some participants have offered guidance on understanding the relationship between acceleration and velocity, while others express confusion about the process of deriving the velocity graph from the acceleration graph. Multiple interpretations of how to approach the problem are being explored.

Contextual Notes

The original poster specifies that graphical analysis should be used exclusively, without employing kinematic equations or integral evaluations, which may limit the methods discussed.

physicslover11
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Homework Statement


The figure below shows the acceleration-versus-time graph for a motorcyclist riding along the x-axis. Assume that at t = 0, x = -1 m and v = 2 m/s.

Unless otherwise specified, use the graphical analysis to solve all the questions below. Do not use the kinematic equations or the functional evaluation of the integral, although, if you happen to know these methods, you may use them to check your graphical result.
1) Plot the velocity-versus-time graph for the first 40 s.
2) a) What is the position of the motorcyclist at t = 40 s? b) What is the distance traveled by the motorcyclist in the first 40 s?
3) a) What is the position of the motorcyclist at t = 15 s? b) Using the kinematic equations, find the position of the motorcyclist at t = 15 s. Compare your answer to that obtained in part a).
4) Roughly sketch the position-versus-time graph for the first 40 s.


Homework Equations


i know that Δv=aΔt, Δx=vΔt


The Attempt at a Solution


i don't know where i should start ! please help
 

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You just find the slope of the velocity graph. Remember, acceleration is the SLOPE of velocity. So from t=0 to t=5, the acceleration is 2. So that means that the velocity graph looks like...?
 
but how do i get the slope of the velocity graph if the velocity graph is what I am looking for?
 
physicslover11 said:
but how do i get the slope of the velocity graph if the velocity graph is what I am looking for?

The value of the acceleration graph is the slope of the velocity graph. That's whatjohnqwertyful was saying.
 

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