How to Handle Zero Eigenvalues in the Generalized Eigenvalue Problem?

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The discussion centers on solving a generalized eigenvalue problem where the matrices A and B yield two zero eigenvalues, indicating redundancy in the system. The user seeks to reduce the system to eliminate these zero eigenvalues before calculating the eigenvalues. It is noted that having zero eigenvalues can be expected based on the ranks of matrices A and B, suggesting that the system can move freely in certain directions. The user acknowledges the physical interpretation of these zero eigenvalues but aims to find a method to simplify the problem beforehand. The conversation highlights the balance between mathematical reduction and physical relevance in eigenvalue problems.
member 399911
Hi all,

I need to find the λ and the ai that solves the Generalized eigenvalue problem

[A]{a}=-λ2 {a}

with

[A]=
Code:
-1289.57,1204.12,92.5424,-7.09489,-25037.4,32022.5,-10004.3,3019.17
1157.46,-1077.94,-0.580522,-78.9482,32022.5,-57353.5,36280.6,-10949.6
166.577,-103.776,1494.41,-1557.21,-10004.3,36280.6,-63053.2,36776.9
-34.4753,-22.407,-1586.37,1643.25,3019.17,-10949.6,36776.9,-28846.5
-22840.1,29254.3,-9328.5,2914.31,-1289.57,1157.46,166.577,-34.4753
29254.3,-51067,31724.8,-9912.15,1204.12,-1077.94,-103.776,-22.407
-9328.5,31724.8,-54591.9,32195.6,92.5424,-0.580522,1494.41,-1586.37
2914.31,-9912.15,32195.6,-25197.7,-7.09489,-78.9482,-1557.21,1643.25

and

=

Code:
0,0,0,0,1875.81,0,0,0
0,5019.07,0,0,0,22535.3,0,0
0,0,-5019.07,0,0,0,22535.3,0
0,0,0,0,0,0,0,937.905
835.2,0,0,0,0,0,0,0
0,5003.02,0,0,0,5019.07,0,0
0,0,5003.02,0,0,0,-5019.07,0
0,0,0,417.6,0,0,0,0

Using mathematica I get for lambdas {75.1098, 35.2687, 34.3082, 15.2013, 4.3281, 1.35478,
5.38827*10^-154, -2.06904*10^-154}

The last two eigenvalues are zero. That made me think that two equations are redundant. I confirmed that with mathematica. Rank of A is 6.

How can I reduce the system? I tried deleting two rows and columns, but for all the combinations the matrix B is singular.
Notice that the first and last column/row of the matrix B have only one value different from zero. Is anything I can do to exploit that?

Best
 
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Why do you think having two zero eigenvalues is an issue? If A has rank 6 and B has rank 4, that is what you would expect to get.

For example if A was the mass matrix and B the stiffness matrix of a structure, the two zero eigenvalues just mean the system can move freely in two (generalized) directions. There is nothing "unphysical" or unreasonable about that.

You don't say what your matrices represent, but if they come from a physics problem the zero eigenvalues probably have a physical interpretation.
 
AlephZero said:
Why do you think having two zero eigenvalues is an issue? If A has rank 6 and B has rank 4, that is what you would expect to get.

For example if A was the mass matrix and B the stiffness matrix of a structure, the two zero eigenvalues just mean the system can move freely in two (generalized) directions. There is nothing "unphysical" or unreasonable about that.

You don't say what your matrices represent, but if they come from a physics problem the zero eigenvalues probably have a physical interpretation.

Thanks AlephZero. The zero eigenvalues do have a physical interpretation and it is related to what you said.

Those special cases are treated separately and I do not need the associated eigenvectors.

What I do up to now is solve the 8x8 system and then remove the zero eigenvalues. I want to know if there is a way reduce the system before calculating the eigenvalues so as to have the nontrivial eigenvalues.

Best
 
I am studying the mathematical formalism behind non-commutative geometry approach to quantum gravity. I was reading about Hopf algebras and their Drinfeld twist with a specific example of the Moyal-Weyl twist defined as F=exp(-iλ/2θ^(μν)∂_μ⊗∂_ν) where λ is a constant parametar and θ antisymmetric constant tensor. {∂_μ} is the basis of the tangent vector space over the underlying spacetime Now, from my understanding the enveloping algebra which appears in the definition of the Hopf algebra...

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