How to integrate sqrt((ax+b)/x) dx (square root of linear fractional function)

Show Steps".In summary, to integrate sqrt((ax+b)/x) dx, let u=\frac{ax+b}{x} and then let v=\sqrt{u}. This will simplify the expression and make it easier to integrate. Alternatively, you can use the website integrals.wolfram.com to find the steps for solving the integral.
  • #1
Holali
9
0
Hi,
simple question, but difficult to find an answer for me

How to integrate sqrt((ax+b)/x) dx ?
a,b constants and x variable

if it matters, I would be happy if you could solve it just for both a,b >0

Thanks
 
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  • #2
Let [itex]u=\frac{ax+b}{x}[/itex]. We're keeping our fingers crossed, there's no other common methods that apply, so this looked like most natural thing to do.

The expression will be a little simpler, but now we try a more common method, which is let [itex]v=\sqrt{u}[/itex]. To find [itex]du[/itex], we usually consider [itex]v^2=u[/itex], to simplify things. I think you will end up with something that you know how to integrate.
 
  • #3
Holali said:
Hi,
simple question, but difficult to find an answer for me

How to integrate sqrt((ax+b)/x) dx ?
a,b constants and x variable

if it matters, I would be happy if you could solve it just for both a,b >0

Thanks

Let x = (b/a)(sinh(t))²
 
  • #4
go here:


integrals.wolfram.com/index.jsp

and enter

sqrt[(a*x+b)/x]

into the text box
 

1. What is a linear fractional function?

A linear fractional function is a type of algebraic function in which the numerator and denominator are both linear expressions. It can be written in the form of f(x) = (ax + b) / (cx + d), where a, b, c, and d are constants.

2. Why is the square root of a linear fractional function difficult to integrate?

The square root of a linear fractional function is difficult to integrate because it involves both a radical and a rational function. This combination makes it challenging to use traditional integration techniques.

3. What is the general approach for integrating sqrt((ax+b)/x) dx?

The general approach for integrating sqrt((ax+b)/x) dx is to first rewrite the function as a sum or difference of simpler fractions, and then use substitution or integration by parts to evaluate the integral.

4. Can the integral of sqrt((ax+b)/x) dx be evaluated using a substitution?

Yes, the integral of sqrt((ax+b)/x) dx can be evaluated using the substitution method. A common substitution is u = sqrt(ax+b) which simplifies the integral to a more manageable form.

5. Are there any special cases to consider when integrating sqrt((ax+b)/x) dx?

Yes, there are a few special cases to consider when integrating sqrt((ax+b)/x) dx. These include when the numerator is a perfect square, when the denominator is a perfect square, and when both the numerator and denominator are perfect squares.

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