MHB How to Minimize the Perimeter of a Rectangle Formed by 24 Unit Squares?

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To minimize the perimeter of a rectangle formed by 24 unit squares, the perimeter function is defined as P(x,y) = 2(x+y), with the area constraint A = xy. The goal is to express the perimeter in terms of one variable by solving the area constraint for either width (x) or height (y). This can be approached using calculus techniques, such as basic minimization methods or Lagrange multipliers. The discussion emphasizes the importance of understanding these mathematical concepts to find the optimal dimensions for the rectangle. The smallest perimeter will result from the most efficient arrangement of the squares.
prasadini
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The perimeter of the smallest rectangle that can be formed using 24 squares 1cm2 of area each is
 
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Re: area

prasadini said:
The perimeter of the smallest rectangle that can be formed using 24 squares 1cm2 of area each is

Have you learned any calculus yet?
 
I am assuming the perimeter is the objective function (the function we wish to optimize (minimize in this case)), so let's give that in terms of the width $x$ and height $y$:

$$P(x,y)=2(x+y)$$

Our constraint is on the area $A$, and so we have:

$$A=xy$$

Now, we can solve the constraint for either variable $x$ or $y$, and then write the perimeter function in one variable, and use Calc I techniques of minimization, or we can use the Calc III technique of Lagrange multipliers.

Can you proceed?